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Anna [14]
3 years ago
10

Please solve what is the slope of the line???​

Mathematics
1 answer:
Feliz [49]3 years ago
3 0

Answer:

The slope is 3/2

Step-by-step explanation:

Pick 2 points and use rise over run.

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Please, my whole grade depends on this question!!!
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Answer:

Y =  1/2 times -3 ( 1 x 5 )

Step-by-step explanation:

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Which inequality is equivalent to −10(x−1)<13?
Nataliya [291]

Answer:

-10<3

Step-by-step explanation:

first distribute the -10 to all the numbers within the parenthesis.

So, -10(x-1)<13 becomes -10x+10<13

Next, combine like terms. then we get -10<3

4 0
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Mr. Richard's science class is conducting a variety of experiments with projectiles and falling objects. Two groups of students
12345 [234]
<span>In general, the height of a projectile is given by

</span>h= -\frac 1 2 g t^2 + v t + h_0
<span>
where </span>h is the height at time t of a projectile shot upward at velocity v from initial height h_0<span>.

The acceleration of gravity </span>g= 9.8 \textrm {m/s}^2 \textrm{ or } g=32\textrm{ feet/s}^2.<span>  We give it a negative sign in the equation because it pulls down.

Let's apply it to each group.

Group A launches a tennis ball straight up with an initial velocity of 19 meters per second.

We have MKS units, positive (upward) velocity and an initial height of 0.

</span>h= -\frac 1 2(9.8) t^2 + (19) t + 0 = -4.9t^2 + 19t
<span>
Group B launches a tennis ball straight up with an initial velocity of 50 feet per second.    Not metric, velocity +50, initial height zero.

</span>h= -16t^2 + 50t
<span>
Group C drops a tennis ball from a height of 19 meters.

MKS, initial height 19, initial velocity zero.

</span>h= -\frac 1 2 g t^2 + v t + h_0 = -4.9 t^2 + 19
<span>
Group D drops a tennis ball from a height of 50 feet. 

</span>h= -16 t^2 + 50
<span>


</span>
6 0
4 years ago
Read 2 more answers
H over 3 plus 16 equals 18
3241004551 [841]

Answer:

If you're looking for H it could be 6

Step-by-step explanation:

bc 6/3+16=18 so 6/3=2 so 2+16=18

3 0
3 years ago
Read 2 more answers
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