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3 years ago

Please please help help me please ASAP ASAP please ASAP thank you!!!!

Mathematics

1 answer:

Natalka [10]3 years ago

5 0

Answer:

1. $\frac{10}{1}$

2.10

3. $\frac{1}{10}$

4. $\frac{15}{1}$

5.15

6. $\frac{1}{15}$

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NEED HELP ASAP!!!! <br> A) 12 sq. cm.<br> B) 6 sq. cm.<br> C) 12 cm<br> D) 6 cm

zaharov [31]

Answer:

its B- 6 sq. cm.

Step-by-step explanation:

1/2 times base times height

1/2 x 4 x 3

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2 years ago

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Jace and Lianna each baked a loaf of bread. jace cut his loaf into halves and lianna cut her loaf into thirds. Jace says they ca

Viktor [21]

Answer:

Jace is correct they can use their loaves of bread to show 1/2 is less than 1/3. Because they have 2 loaves of bread

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2 years ago

Find the solution to: -2x+7<-41

Karolina [17]

Answer:

x>24

Step-by-step explanation:

Solve like a normal equation :)

-2x<-48

Now we divide.

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Note: Whenever dividing by a negative, you have to flip the sign of the inequality!

x>24

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3 years ago

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Using these complex zeros (1,1,-1/2,2+i,2-i) factor f(x)=-2x^5 +11x^4 -22x^3 +14x^2 +4x -5

Marianna [84]

$\bf \begin{cases}
x=1\implies &x-1=0\\
x=1\implies &x-1=0\\
x=-\frac{1}{2}\implies 2x=-1\implies &2x+1=0\\
x=2+i\implies &x-2-i=0\\
x=2-i\implies &x-2+i=0
\end{cases}
\\\\\\
(x-1)(x-1)(2x+1)(x-2-i)(x-2+i)=\stackrel{original~polynomial}{0}
\\\\\\
(x-1)^2(2x+1)~\stackrel{\textit{difference of squares}}{[(x-2)-(i)][(x-2)+(i)]}$

$\bf (x^2-2x+1)(2x+1)~[(x-2)^2-(i)^2]
\\\\\\
(x^2-2x+1)(2x+1)~[(x^2-4x+4)-(-1)]
\\\\\\
(x^2-2x+1)(2x+1)~[(x^2-4x+4)+1]
\\\\\\
(x^2-2x+1)(2x+1)~[x^2-4x+5]
\\\\\\
(x^2-2x+1)(2x+1)(x^2-4x+5)$

of course, you can always use (x-1)(x-1)(2x+1)(x²-4x+5) as well.

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3 years ago

A sector with a radius of 8 cm has an area of 56pi cm2. What is the central angle measure of the sector in radians?

Maurinko [17]

Answer:

$\frac{7\pi}{4}$ .