Answer:
The required specific heat is 196.94 joule per kg per °C
Step-by-step explanation:
Given as :
The heat generated = Q = 85.87 J
Mass of substance (m)= 34.8 gram = 0.0348 kg
Change in temperature = T2 - T1 = 34.29°C - 21.76°C = 12.53°C
Let the specific heat = S
Now we know that
Heat = Mass × specific heat × change in temperature
Or, Q = msΔt
Or, 85.87 = (0.0348 kg ) × S × 12.53°C
Or , 85.87 = 0.4360 × S
Or, S =
∴ S = 196.94 joule per kg per °C
Hence the required specific heat is 196.94 joule per kg per °C Answer
Answer: $11.25
Step-by-step explanation:
Since the sneakers were on sale for 15% less, the amount she bought them will be:
= (100% - 15%) × $75
= 85% × $75
= 0.85 × $75
= $63.75
Therefore, the amount she saved will then be:
= $75 - $63.75
= $11.25
She saved $11.25
Answer:
13
Step-by-step explanation:
refer the image attached below
The Answer to this problem is BN=3.8 Units.