C = 1.14 M , T = 10 + 273.15 = 283.15 K salt concentration = 176 mg /L NaCl
π total = CRT = 1.14 x 0.0821 x 283.15 = 26.5 atm
mass of NaCl = 176 mg = 0.176 g
Molarity =
maximum concentration allowed C = 3.0366 x 10⁻³ M
π max. conc. = 2 x 3.0366 x 10⁻³ x 0.0821 x 283.15 = 0.141 atm
π external = π total - π max. conc.
= 26.5 - 0.141 = 26.3 atm
if it is already as low as it can go
Answer:
= 5.26 × 10^-7 M
Explanation:
We know that;
[H3O+][OH-] = 1 x 10^-14
Therefore;
Given; OH− concentration = 1.9x10^−8 M
Then; [H3O+] = (1 x 10^-14)/[OH-]
= (1 x 10^-14)/(1.9x10^−8)
= 5.26 × 10^-7 M
Answer:
all bulbs will light up once the switch is closed