A. Yes B.no Answer: yes!!!!!!!
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Answer:
The sample of students required to estimate the mean weekly earnings of students at one college is of size, 3458.
Step-by-step explanation:
The (1 - <em>α</em>)% confidence interval for population mean (<em>μ</em>) is:
The margin of error of a (1 - <em>α</em>)% confidence interval for population mean (<em>μ</em>) is:
The information provided is:
<em>σ</em> = $60
<em>MOE</em> = $2
The critical value of <em>z</em> for 95% confidence level is:
Compute the sample size as follows:
Thus, the sample of students required to estimate the mean weekly earnings of students at one college is of size, 3458.
Above step we use "Multiplication property of equality"
In the above step we "Simplify on both sides of equation"
In the above step we use "Distribution property"
The above step is the result of using "Subtraction property of equality"
Above step is result of "Combining the like terms"
Above step is the result of using "Division property of equality"
Above step is result of "Simplifying fractions on either side of equation"
Let's first find out their factors.
90's factors are :
190's factors are :
The common factors of 90 and 190 are :
1,2,5 and 10.
The greatest one among these is, 10. So the greatest factor of 90 and 190 is 10.
90's factors are :
190's factors are :
The common factors of 90 and 190 are :
1,2,5 and 10.
The greatest one among these is, 10. So the greatest factor of 90 and 190 is 10.