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3 years ago

The coordinates of trapezoid EFGH are E(8, 8), F(8, 10), G(1, 6), and H(4, 1). The image of EFGH under dilation is E'F'G'H'.

1 answer:

7 0

The coordinates of vertex F' would be (4,5). Since your original coordinates are twice the new coordinates, you'd have to divide the old coordinates by 2 to get the new coordinates of (4,5).

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Consider the inequality -5(x+7) <-10. write an inequalityrepresenting the soulution for x.

Gwar [14]

Answer:

x > -5

Step-by-step explanation:

You multiply both sides by -1

Simplify

Divide both sides by 5

Simplify

Subtract 7 from both sides

Simplify

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2 years ago

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3 years ago

McKenzie makes and sells quilts at an art fair. The materials for each quilt cos t$30.50. She sells the quilts for $80. If "n" r

Nitella [24]

Answer:

Total profits = 49.50n

Step-by-step explanation:

Cost of each quilt = $30.50

Selling price of each quilt = $80

Profits = selling price - cost price

= $80 - $30.50

= $49.50

Profits = $49.50

If n = number of quilts she sells

which expression could be used to represent her total profits?

Total profits = profits of each quilt × number of quilt sold

= $49.50 × n

= 49.50n

Total profits = 49.50n

4 0

3 years ago

Jessica and Nancy are members of different video game libraries. Jessica pays a membership fee of $40, and she pays $5 for every

DaniilM [7]

36 because I did this on my test before

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3 years ago

Helppppppppppppppppppp please

Svetlanka [38]

Answer:

$\sqrt[]{\frac{x+8}{4}}-3$

Step-by-step explanation:

$g(x)=4(x+3)^2-8$

First rewrite $g(x)$ as y

$y=4(x+3)^2-8$

Now swap y and x

$x=4(y+3)^2-8$

Add 8 on both sides.

$x+8=4(y+3)^2-8+8$

$x+8=4(y+3)^2$

Divide by 4.

$\frac{x+8}{4} =\frac{4(y+3)^2}{4}$

$\frac{x+8}{4}=(y+3)^2$

Extract the square root on both sides.

$\sqrt[]{\frac{x+8}{4}}=\sqrt[]{(y+3)^2}$

$\sqrt[]{\frac{x+8}{4}}=y+3$

Subtract 3 on both sides.

$\sqrt[]{\frac{x+8}{4}}-3=y+3-3$

$\sqrt[]{\frac{x+8}{4}}-3=y$

4 0

3 years ago