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Aleonysh [2.5K]
3 years ago
12

15 POINTS to solve this CONSTRUCTION.

Mathematics
1 answer:
White raven [17]3 years ago
5 0

Answer:

4 PS ≅ RQ

I hope it helps

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I understand some of this but this ones got me stumped i tried pemdas but im still lost
Mandarinka [93]
Just replace x with its given value:

9x^{2}-4x-3~~~~\text{where }x=-2\\ \\ \\ 9\cdot (-2)^{2}-4\cdot (-2)-3\\ \\ =9\cdot 4+8-3\\ \\ =36+8-3\\ \\ =41
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Find the missing value.<br> Hint: Use the number line to find the missing value.<br> -5=_+6
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Megan has 30 brownies and 42 cupcakes to package she want to put the same numbers of brownies and if cupcakes in each box what i
kap26 [50]

Answer:

6!!!

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3 years ago
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If someone could help me with number 26...
Volgvan
Given:
\text{sec x} -  \sqrt{\text{2 sec x}-1} =0

Solution:
To solve the equation, it would be best if we remove the root. We remove the root by squaring the equation, but first we need to move the root and the content to the left side.
\text{sec x} -  \sqrt{\text{2 sec x}-1} =0
\text{sec x} =  \sqrt{\text{2 sec x}-1}

Then square both side to remove the root
\text{sec}^2 x= \text{2 sec x}-1

After removing the root, move all terms to the left side
sec² x - 2 sec x + 1 = 0

Do factorization, remember that
a² - 2a + 1 = (a - 1)²
So,
sec² x - 2 sec x + 1 = 0
(sec x - 1)² = 0
sec x - 1 = 0
sec x = 1
\dfrac{1}{\text{cos x}} = 1
cos x = 1
cos x = cos 0°
x = 0°
8 0
3 years ago
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