Answer:
y=2x-3
Step-by-step explanation:
1. find the slope
6x-3y=21
-3y=-6x+21 divide both sides by -3
y=2x-7
slope is 2
2.y-5=2(x-4)
y-5=2x-8
y=2x-8+5
y=2x-3
PARALLEL lines have the same slope
It doesn't, it ends after 32 digits after 0.
Answer:
![C(x)=24,000+19,200x](https://tex.z-dn.net/?f=C%28x%29%3D24%2C000%2B19%2C200x)
Step-by-step explanation:
<u>Mathematical Modeling</u>
To model a real-life situation, a mathematical model can be constructed in such a way it accurately represents the variables measured in the system.
This problem requires to build a model for the yearly cost of a small and successful business.
The first data is the fixed monthly cost or the money the owner must pay regardless of the number of employees he hires. This cost includes shipping supplies and products for $2,000. To operate for a full year, the fixed cost is 12*$2,000=$24,000.
The other component of the cost function is the variable cost of x employees. Given each employee costs $1,600 each month, having x employees cost 1,600x each month. For a full year, the variable cost will be
12*1,600x=19,200x.
We finally form the total cost function:
![\boxed{C(x)=24,000+19,200x}](https://tex.z-dn.net/?f=%5Cboxed%7BC%28x%29%3D24%2C000%2B19%2C200x%7D)
Let's solve for h.
h
p
=
p
3
+
4
p
2
−
2
Step 1: Divide both sides by p.
h
p
p
=
p
3
+
4
p
2
−
2
p
h
=
p
3
+
4
p
2
−
2
p
Answer:
h
=
p
3
+
4
p
2
−
2
p
Answer:
20/7 days (just less than 3 days)
Step-by-step explanation:
Recall that (1 job) = (rate)(time), so time = (1 job) / (rate).
Set up and solve the following equation:
1 job
------------------------------- = time required for 2 pumps working together
1 job 1 job
---------- + -------------
4 days 10 days
This comes out to:
1 job
------------------------------------------- = time required
10 job-days 4 job-days
------------------ + -----------------
40 days 40 days
or:
1 job
-------------------- = (40/14) days, or 20/7 days (just less than 3 days)
14 job·days
-----------------
40 days