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Kryger [21]
3 years ago
5

What is 9/12 as a decimal

Mathematics
1 answer:
UNO [17]3 years ago
8 0

Answer:

.75

Step-by-step explanation:

u just do 9÷12 to find a decimal

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Evalue f(x)=(-2)^2-3(-2)+5/(-2)^2+1
Nina [5.8K]
F(x)=4+6+5/4+1
F(x)=4+6+5/5
F(x)=10+1=11

Answer =11
8 0
2 years ago
15.3+x=1.3-x so how do I solve it
anzhelika [568]

Answer:

-7

Step-by-step explanation:

Let's try getting rid of the numbers to isolate the x.

Add x on both sides to get rid of the x on the right side and to get 2x on the left side. This leaves us with 15.3 + 2x = 1.3

Subtract 15.3 on both sides to get rid of the 15.3 on the left side.

This would leave us with 2x = -14

Divide 2 on both sides to isolate the x.

The answer is x = -7

3 0
3 years ago
Read 2 more answers
Ashton has an offer to buy an item with a sticker price of $4900 by paying
Alla [95]
B
The correct answer is b
6 0
3 years ago
What numbers add up to-15 but when multiplied gives me-54
OLga [1]
The answer would be -18 and 3
6 0
3 years ago
At a race track you have the opportunity to buy a ticket that requires you to pick the first and second place horses in the firs
rewona [7]

Answer:

4032 different tickets are possible.

Step-by-step explanation:

Given : At a race track you have the opportunity to buy a ticket that requires you to pick the first and second place horses in the first two races. If the first race runs 9 horses and the second runs 8.

To find : How many different tickets are possible ?

Solution :

In the first race there are 9 ways to pick the winner for first and second place.

Number of ways for first place - ^9C_1=9

Number of ways for second place - ^8C_1=8

In the second race there are 8 ways to pick the winner for first and second place.

Number of ways for first place - ^8C_1=8

Number of ways for second place - ^7C_1=7

Total number of different tickets are possible is

n=9\times 8\times 8\times 7

n=4032

Therefore, 4032 different tickets are possible.

8 0
2 years ago
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