F(x)=4+6+5/4+1
F(x)=4+6+5/5
F(x)=10+1=11
Answer =11
Answer:
-7
Step-by-step explanation:
Let's try getting rid of the numbers to isolate the x.
Add x on both sides to get rid of the x on the right side and to get 2x on the left side. This leaves us with 15.3 + 2x = 1.3
Subtract 15.3 on both sides to get rid of the 15.3 on the left side.
This would leave us with 2x = -14
Divide 2 on both sides to isolate the x.
The answer is x = -7
The answer would be -18 and 3
Answer:
4032 different tickets are possible.
Step-by-step explanation:
Given : At a race track you have the opportunity to buy a ticket that requires you to pick the first and second place horses in the first two races. If the first race runs 9 horses and the second runs 8.
To find : How many different tickets are possible ?
Solution :
In the first race there are 9 ways to pick the winner for first and second place.
Number of ways for first place - 
Number of ways for second place - 
In the second race there are 8 ways to pick the winner for first and second place.
Number of ways for first place - 
Number of ways for second place - 
Total number of different tickets are possible is


Therefore, 4032 different tickets are possible.