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bearhunter [10]
3 years ago
9

G)Find thethe coefficient of y^5 in theexpansion of (3+2y)^6​

Mathematics
1 answer:
hodyreva [135]3 years ago
3 0

Answer:

2

Step-by-step explanation:

A coefficient is a number of times a variable. So in this equation. 2 is being multiplied by y. so 2 is the coefficient.

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a carpebter has a board 2 meter needs to cut it in 8 equal pieces how many centerimeters long will each piece be
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Circles in the Coordinate Plane<br> Acellus<br> Complete the equation of this circle:<br> А<br> 1
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Answer:

(x -+2)² + (y - 4)² = 36

Step-by-step explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k) are the coordinates of the centre and r is the radius

Here (h, k ) = (- 2, 4) and r = 6 , then

(x - (- 2))² + (y - 4)² = 6² , that is

(x + 2)² + (y - 4)² = 36 ← equation of circle

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2 years ago
Congruent Triangles and Proofs<br><br> Given: JK bisects
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Answer:

Step-by-step explanation:

1S. JM bisects ∠ KJL and  ∠JMK ≅ ∠JML

1R. Given

2S. ∠KJM ≅ ∠LJM

2R. Angle bisectors form ≅ ∠s

3S. JM≅JM

3R. Reflexive Propriety ( segment is ≅ with itself)

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4R. ASA theorem of congruency

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7 0
3 years ago
the number of three-digit numbers with distinct digits that be formed using the digits 1,2,3,5,8 and 9 is . The probability that
jolli1 [7]

Answer:

a)120

b)6.67%

Step-by-step explanation:

Given:

No. of digits given= 6

Digits given= 1,2,3,5,8,9

Number to be formed should be 3-digits, as we have to choose 3 digits from given 6-digits so the no. of combinations will be

6P3= 6!/3!

      = 6*5*4*3*2*1/3*2*1

      =6*5*4

      =120

Now finding the probability that both the first digit and the last digit of the three-digit number are even numbers:

As the first and last digits can only be even

then the form of number can be

a)2n8 or

b)8n2

where n can be 1,3,5 or 9

4*2=8

so there can be 8 three-digit numbers with both the first digit and the last digit even numbers

And probability = 8/120

                          = 0.0667

                          =6.67%

The probability that both the first digit and the last digit of the three-digit number are even numbers is 6.67% !

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