Answer:
x= 3
y=2
Step-by-step explanation:
-3x + 9y = 9 ----------- equation 1
3x + 2y = 13--------------- equation 2
In Matrix Form
![\left[\begin{array}{cc}-3&9\\3&2\end{array}\right] \left[\begin{array}{c}x\\y\end{array}\right] = \left[\begin{array}{c}9\\13\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-3%269%5C%5C3%262%5Cend%7Barray%7D%5Cright%5D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7Dx%5C%5Cy%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D9%5C%5C13%5Cend%7Barray%7D%5Cright%5D)
Let A = ![\left[\begin{array}{cc}-3&9\\3&2\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-3%269%5C%5C3%262%5Cend%7Barray%7D%5Cright%5D)
X = ![\left[\begin{array}{c}x\\y\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7Dx%5C%5Cy%5Cend%7Barray%7D%5Cright%5D)
and B = ![\left[\begin{array}{c}9\\13\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D9%5C%5C13%5Cend%7Barray%7D%5Cright%5D)
Then Mathematically AX= B
or X= A⁻¹ B
Where A⁻¹ = Adjacent A/ mod of A
Adjacent A = ![\left[\begin{array}{cc}2&-9\\-3&-3\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D2%26-9%5C%5C-3%26-3%5Cend%7Barray%7D%5Cright%5D)
Mod Of A= -6 - (27) = -33 which is not equal to zero
so Putting These values in the given formula
X= 1/-33
Now Multiplying Rows and Columns
= -1/33 ![\left[\begin{array}{cc}2*9+- 9*13\\-3*9 +- 3*13\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D2%2A9%2B-%209%2A13%5C%5C-3%2A9%20%2B-%203%2A13%5Cend%7Barray%7D%5Cright%5D)
Solving the Matrix we get
= -1/33 ![\left[\begin{array}{cc}18-117\\-27-39\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D18-117%5C%5C-27-39%5C%5C%5Cend%7Barray%7D%5Cright%5D)
= -1/33 ![\left[\begin{array}{cc}-99\\-66\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-99%5C%5C-66%5Cend%7Barray%7D%5Cright%5D)
From Here we find x= 99/33 or 3
and y = 66/33= 2
First, you need to find out how much ribbon she has total. Because there are two spools, you multiply 24 x 2. The answer for that is 48. Then you have to figure out how many bows she can make. Each bow uses 1/8 of a piece of yard of ribbon, so you can divide 48 by 8. Your answer would then be 6 bows.
Here are the equations.
24*2 = X
X/8 = B
Where X represents the yards of ribbon available and B represents the number of bows that Mari can make.
Answer:
154
Step-by-step explanation:
just divide 1232 and 8
(long division)
Answer:
The value of x° = 134°
Step-by-step explanation:
Given the angles of a quadrilateral
We know that the sum of interior angles in a quadrilateral is 360°.
so
100° + 51° + 75° + x° = 360°
226° + x° = 360°
subtracting 226° from both sides
226° + x° - 226° = 360° - 226°
x° = 134°
Therefore, the value of x° = 134°
VERIFICATION:
100° + 51° + 75° + 134° = 360°
360°= 360°
