Answer: T.S.A = 4512cm^2
volume = 18900cm^3
weight = 17.01 kg
Step-by-step explanation:
T.S.A of cuboid = 2(lb+bh+lh)
= 2(42x25 + 25x18 + 42x18)
=2(1050 + 450 + 756)
=2 x 2256
= 4512cm^2
to find weight, we've to find the volume of the ice cube
therefore, volume of a cuboid = lbh
=42 x 25 x 28
=18900cm^3
weight of 1cm^3 of ice = 0.9grams
therefore weight of 18900cm^3 of ice = 18900 x 0.9
= 17010 grams = 17.01kg
Hope it helped u,
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Answer:
B
Step-by-step explanation:
got it right on edg
To find the interior angle, you use the formula ((n - 2) x 180) / n (where n is the number of sides).
So, ((20 - 2) x 180) / 20 = 162
To find the exterior angle, you merely take away the interior angle from 180.
180 - 162 = 18, so the exterior angle is 18 degrees
Another, easier, way is to just divide 360 by n. All exterior angles always add to 360. Thus, 360 / 20 = 18 degrees
-5(x+5) I believe would be the answer