Answer:
The 80% confidence interval for the mean number of toys purchased each year is between 7.5 and 7.7 toys.
Step-by-step explanation:
We have that to find our 
level, that is the subtraction of 1 by the confidence interval divided by 2. So:
Now, we have to find z in the Ztable as such z has a pvalue of 
.
That is z with a pvalue of 
, so Z = 1.28.
Now, find the margin of error M as such
In which 
is the standard deviation of the population and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 7.6 - 0.1 = 7.5
The upper end of the interval is the sample mean added to M. So it is 7.6 + 0.1 = 7.7
The 80% confidence interval for the mean number of toys purchased each year is between 7.5 and 7.7 toys.
Answer:
h = -4
Step-by-step explanation:
7h-5(3h-8) = 72
Distribute
7h - 15h +40 = 72
Combine like terms
-8h +40 = 72
Subtract 40 from each side
-8h+40-40 = 72-40
-8h = 32
Divide each side by -8
-8h/-8 = -32/-8
h = -4
We have the following equation:
s = ut + 1 / 2at ^ 2
Clear a for the equation:
1 / 2at ^ 2 = s-ut
at ^ 2 = 2s-2ut
a = 2s / t ^ 2-2ut / t ^ 2
Rewriting:
a = (2s-2ut) / (t ^ 2)
Answer:
An equation that represents a in terms of other variables is:
C. 2s-2ut / t ^ 2
Okay so, your answer should be 10. I wrote out each step but my handwriting is bad. let me know if I need to redo it for you!
