Find the equation of the line that
2 answers:
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What is the equation of the line parallel to y=-5x-9 and contains the point (-3, -3)?
First of all, parallel lines have the exact same slope.
So we know the slope of the line:- -5.
(enter -5, It's the number that belongs in the green box)
How about the y-intercept?
Well, since we're given the slope and a point that the line intersects, we can write the line's equation in point-slope form:-
y-y1=m(x-x1)
y-(-3)=-5(x-(-3)
y+3=-5(x+3)
y+3=-5x-15
y=-5x-18
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As given,
Loan amount is = $45000
Rate of interest = 8.5%
So, Tony's mortgage will attract an interest of:
= $3825 (this is yearly)
And for 1st month it will be = = $318.75
As given, the first month's payment is $390.60 and this covers the interest Additional amount ($390.60 - $318.75 = $71.85) is a payment against the principle.
Hence, the new principle after the 1st month is $71.85 less than $45000
= 45000-71.85 = $44928.15
Hence, the last option $44928.15 is the correct answer.
Answer:
The proportion of the chocolate bars produced that have mass within one standard deviation of the mean is 0.6826 = 68.26%.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
A consumer organization finds that the mass of the chocolate bar is normally distributed with a mean of 200.4 g and a standard deviation of 0.05 g.
This means that
a) Find the proportion of the chocolate bars produced that have mass within one standard deviation of the mean.
pvalue of Z when X = 200.4 + 0.05 = 200.9 subtracted by the pvalue of Z when X = 200.4 - 0.05 = 199.9.
X = 200.9
has a pvalue of 0.8413
X = 199.9
has a pvalue of 0.1587
0.8413 - 0.1587 = 0.6826
The proportion of the chocolate bars produced that have mass within one standard deviation of the mean is 0.6826 = 68.26%.