Find the equation of the line that
2 answers:
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What is the equation of the line parallel to y=-5x-9 and contains the point (-3, -3)?
First of all, parallel lines have the exact same slope.
So we know the slope of the line:- -5.
(enter -5, It's the number that belongs in the green box)
How about the y-intercept?
Well, since we're given the slope and a point that the line intersects, we can write the line's equation in point-slope form:-
y-y1=m(x-x1)
y-(-3)=-5(x-(-3)
y+3=-5(x+3)
y+3=-5x-15
y=-5x-18
<h3>Good luck.</h3>- - - -- - - - - - - - - - - - - - -- - - - - - - - - - - - -- - - - - - - - - - - - - - -- - - - -
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The equation is:
where -9.8m/sec² is the acceleration due to gravity, v₀ is the initial velocity, and h₀ is the initial height. We will go from the assumption that the rocket is launched from the ground, so h₀=0, and we are told that the initial velocity, v₀, is 42. This gives us:
We will use the quadratic formula to solve this. The quadratic formula is:
Plugging in our information we have:
x=0 is when the rocket is launched; x=4.3 is when the rocket lands.
The equation is:
where -9.8m/sec² is the acceleration due to gravity, v₀ is the initial velocity, and h₀ is the initial height. We will go from the assumption that the rocket is launched from the ground, so h₀=0, and we are told that the initial velocity, v₀, is 42. This gives us:
We will use the quadratic formula to solve this. The quadratic formula is:
Plugging in our information we have:
x=0 is when the rocket is launched; x=4.3 is when the rocket lands.