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hichkok12 [17]
3 years ago
13

HELP ME WITH THIS FOR A BRAINLIEST

Physics
1 answer:
andrew11 [14]3 years ago
3 0

Option C: Runs up the slipway 5 s

hope this helped :)

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The international Space Station (ISS) orbits the Earth once every 90 mins at an altitude of 409 km. How high would it have to be
Oksi-84 [34.3K]

It would have to be 36,719 Km high in order to be to be in geosynchronous orbit.

To find the answer, we need to know about the third law of Kepler.

<h3>What's the Kepler's third law?</h3>
  • It states that the square of the time period of orbiting planet or satellite is directly proportional to the cube of the radius of the orbit.
  • Mathematically, T²∝a³
<h3>What's the radius of geosynchronous orbit, if the time period and altitude of ISS are 90 minutes and 409 km respectively?</h3>
  • The time period of geosynchronous orbit is 24 hours or 1440 minutes.
  • As the Earth's radius is 6371 Km, so radius of the ISS orbit= 6371km + 409 km = 6780km.
  • If T1 and T2 are time period of geosynchronous orbit and ISS orbit respectively, a1 and a2 are radius of geosynchronous orbit and ISS orbit, as per third law of Kepler, (T1/T2)² = (a1/a2)³
  • a1= (T1/T2)⅔×a2

           = (1440/90)⅔×6780

           = 43,090 km

  • Altitude of geosynchronous orbit = 43,090 - 6371= 36,719 km

Thus, we can conclude that the altitude of geosynchronous orbit is 36,719km.

Learn more about the Kepler's third law here:

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6 0
2 years ago
The net force of a heavy, stationary box is?
Leto [7]

Answer:

gravity

Explanation:

7 0
3 years ago
A toy helium balloon is initially at a temperature of T = 24o C. Its initial volume is 0.0042 m3 (It is a 10 cm radius sphere).
Anettt [7]

Answer:

T_{f} = 335.780\,K\,(62.630\,^{\textdegree}C)

Explanation:

Let assume that air behaves ideally. The equation of state of ideal gases is:

P\cdot V = n\cdot R_{u}\cdot T

Where:

P - Pressure, in kPa.

V - Volume, in m³.

n - Quantity of moles, in kmol.

R_{u} - Ideal gas constant, in \frac{kPa\cdot m^{3}}{kmol\cdot K}.

T - Temperature, in K.

Since there is no changes in pressure or the quantity of moles, the following relationship between initial and final volumes and temperatures is built:

\frac{V_{o}}{T_{o}} = \frac{V_{f}}{T_{f}}

The final temperature is:

T_{f} = \frac{V_{f}}{V_{o}}\cdot T_{o}

T_{f} = 1.13\cdot (297.15\,K)

T_{f} = 335.780\,K\,(62.630\,^{\textdegree}C)

7 0
4 years ago
Read 2 more answers
Hey can someone help plzzzzz​
ohaa [14]

Answer:

Potential Energy stored = mgh ; m : mass, g : gravitational acceleration (let 10m/s) , h : height

Hence,

Energy Stored in the ball = mgh = (2*10*4) J

= 80 Joules!

8 0
3 years ago
Read 2 more answers
an object has 5.00 kg*m/s of momentum. if you double the mass and double the velocity, how much momentum would it have PLEASE HE
KIM [24]

The final momentum is 20.00 kg*m/s

Explanation:

The momentum of an object is given by:

p=mv

where

m is the mass of the object

v is its velocity

For the object in the problem, the initial momentum is

p=mv=5.00 kg m/s

Then, the mass is doubled:

m' = 2m

And the velocity is also doubled:

v' = 2v

So, the new momentum will be:

p'=m'v'=(2m)(2v)=4(mv) = 4p = 4(5.00)=20 kg m/s

So, the final momentum is 4 times the initial momentum.

Learn more about momentum:

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6 0
4 years ago
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