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3 years ago

Find the distance between the two points

Mathematics

1 answer:

Levart [38]3 years ago

7 0

Answer:

Dab = square root of ( xa - xb )^2 + (ya - yb)^2

square root of [ (-4) - 4 ]^2 + [ 2 - (-2) ] ^2

square root of 80

• Ab is = square root of 80 units

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Please find the answer

Serggg [28]

Answer:

x^3 + 1/x^3 = 488

Step-by-step explanation:

x^2 + 1/x^2 = 62
x^2 + 1/x^2 + 2 = 64
( adding 2 in both sides )
(x + 1/x ) ^2 = 64
x + 1/x = 8

now,

( x+ 1/x ) ^ 3 = 512
x^3 + 1/x^3 + 3 × x × 1/x ( x + 1/x )
x^3 + 1/x^3 + 3 ( 8 )
( since x + 1/x = 8 )
x^3 + 1/x^3 + 24 = 512
x^3 + 1/x^3 = 488

hence, we got x^3 + 1/x^3 = 488

8 0

3 years ago

Assume the resting heart rates for a sample of individuals are normally distributed with a mean of 75 and a standard deviation o

Shalnov [3]

Answer:

a) 0.975

b) 0.16

c) 0.475

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviation of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean = 75

Standard deviation = 5

We also have that since the normal distribution is symmetric, 50% of the measures are below the mean and 50% are above.

a. The relative frequency of rates less than 85 using the 68-95-99.7 rule is

85 is two standard deviations above the mean.

So all the 50% below the mean is below 85

And of the 50% above the mean, 95% is less than 85. So

0.5 + 0.95*0.5 = 0.975

b. The relative frequency of rates greater than 80 using the 68-95-99.7 rule is

80 is one standard deviations above the mean.

Of the 50% above the mean, 68% is less than 80. So 100-68 = 32% is more than 80.

0.32*0.5 = 0.16.

c. The relative frequency of rates between 65 and 75 using the 68-95-99.7 rule is

Within the mean and two standard deviations below the mean.

So 95% of 50%

0.95*0.5 = 0.475

6 0

4 years ago

Can someone please help me

Georgia [21]

It’s 1/2 because every time the x variable goes up 1, the y variable goes up 2

4 0

4 years ago

Read 2 more answers

A cat is stuck on the roof. If . the ladder is 18 feet long and must be placed nine feet away from the building. How high can th

adell [148]

Answer: 14.8

Did it on USA test prep

5 0

3 years ago

Read 2 more answers

Car X weighs 136 pounds more than car Z. Car Y weighs 117 pounds more than car Z. The total weight of all three cars is 9439 pou

Aleksandr [31]

Let x, y and z denote the weighs of car X, car Y and car Z, respectively.

We know that car X weighs 136 more than car Z, this can be express by the equation:

$x=z+136$

We also know that Y weighs 117 pounds more than car Z, this can be express as:

$y=z+117$

Finally, we know that the total weight of all the cars is 9439, then we have:

$x+y+z=9439$

Hence, we have the system of the equations:

$\begin{gathered} x=z+136 \\ y=z+117 \\ z+y+z=9439 \end{gathered}$

To solve the system we can plug the values of x and y, given in the first two equations, in the last equation; then we have:

$\begin{gathered} z+136+z+117+z=9439 \\ 3z=9439-136-117 \\ 3z=9186 \\ z=\frac{9186}{3} \\ z=3062 \end{gathered}$

Now that we have the value of z we plug it in the first two equations to find x and y:

$\begin{gathered} x=3062+136=3198 \\ y=3062+117=3179 \end{gathered}$

Therefore, car X weighs 3198 pound, car Y weighs 3179 pounds and car Z weighs 3062 pounds.

4 0

1 year ago