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-Dominant- [34]
3 years ago
15

HELP PLEASE!!! Find the number(s) with the following property: two times the sum of 18 and a number is 8 greater than nine times

the same number.
Mathematics
1 answer:
vovangra [49]3 years ago
4 0

Answer:

number is 4

Step-by-step explanation:

let 'n' = the number

2(n + 18) = 9n + 8

2n + 36 = 9n + 8

36 = 7n + 8

28 = 7n

n = 4

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Evaluate <br> H(t)=-20+11t<br> H(11)=
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Answer:

H(11)=101

Step-by-step explanation:

The function we have is:

H(t)=-20+11t

and we need to find the value of

H(11)

this is evaluating the function H(t) when the value of t is t=11

So, first we substitute t=11 in H(t):

H(11)=-20+11(11)

we solve the expression:

H(11)=-20+121\\H(11)=101

the answer is that when t=11, the function has the value H(11)=101

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EXPLANATION

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