Find the measures of the acute angle of the right triangle shown

Theo fills a large box with boxes of staples. The volume of each box of staples is 120 cu cm. Estimate the volume of the large b

riadik2000 [5.3K]

I saw the image. The large box is filled with 6 columns of staples which has 5 box of staple each.

6colums * 5boxes/column = 30 boxes of staples.

30 boxes * 120 cu cm/box= 3,600 cu cm.

The estimated volume of the large box is 3,600 cu cm.

8 0

3 years ago

If a trend line has a slope of -4, what is true about the data? Select all that apply.

Allisa [31]

Answer:

$\displaystyle The\:data\:is\:going\:down\:from\:left\:to\:right.$

Step-by-step explanation:

We will take $\displaystyle y = -4x$ for instance. As you can see in the graph, all trends decrease from left to right.

I am joyous to assist you anytime.

8 0

3 years ago

Help with this question please and thank :>

Illusion [34]

Answer:

13.858

Step-by-step explanation:

The steps are listed in the graphic.

4 0

3 years ago

If f(x) = 2(34) + 1, what is the value of f(2)? <br>

larisa86 [58]

I believe that f(2) is 34.5

f(2) = 2(34) + 1
f(2) = 68 + 1
f(2) = 69
f = 69/2
f = 34.5

I AM NOT SURE

3 0

2 years ago

Suppose a baker claims that the average bread height is more than 15cm. Several of this customers do not believe him. To persuad

laila [671]

Answer:

$17-2.262\frac{1.9}{\sqrt{10}}=15.641$

$17+2.262\frac{1.9}{\sqrt{10}}=18.359$

So on this case the 95% confidence interval would be given by (15.641;18.359)

And since the lower limit for the confidence interval is higher than 15 we can conclude that at 5% of significance the true mean is higher than 15 cm

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=17$ represent the sample mean

$\mu$ population mean (variable of interest)

s=1.9 represent the sample standard deviation

n=10 represent the sample size

Confidence interval

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=10-1=9$

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,9)".And we see that $t_{\alpha/2}=2.262$

Now we have everything in order to replace into formula (1):

$17-2.262\frac{1.9}{\sqrt{10}}=15.641$

$17+2.262\frac{1.9}{\sqrt{10}}=18.359$

So on this case the 95% confidence interval would be given by (15.641;18.359)

And since the lower limit for the confidence interval is higher than 15 we can conclude that at 5% of significance the true mean is higher than 15 cm

4 0

3 years ago