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4 years ago

15

HELP!!

1 answer:

maksim [4K]4 years ago

8 0

Equation: 4x+15=31
I have included a picture of my work since explaining might be difficult but the way I solved this if the beginning of algebra and I hope it makes sense.
Your welcome, Katy

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Simplify the expression (sqrt 3 + i) (sqrt 3 - i) and write the result in the form a + bi.

Keith_Richards [23]

Answer:

Answer is D

Step-by-step explanation:

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4 0

3 years ago

Use inverse operations to solve the following equations HELP NOW!!!!

Doss [256]

Y=-7

41=6-5y
35=-5y
-7=y

3 0

3 years ago

What are the solutions of the equation x4 - 9x2 + 8 = 0? Use u substitution to solve.

Sedbober [7]

Answer:

$\large\boxed{B.\ x=\pm1\ and\ x=\pm2\sqrt2}$

Step-by-step explanation:

$x^4-9x^2+8=0\\\\x^{2\cdot2}-9x^2+8=0\qquad\text{use}\ (a^n)^m=a^{nm}\\\\(x^2)^2-9x^2+8=0\\\\\text{substitute}\ x^2=t\geq0\\\\t^2-9t+8=0\\\\t^2-t-8t+8=0\\\\t(t-1)-8(t-1)=0\\\\(t-1)(t-8)+0\iff t-1=0\ \vee\ t-8=0\\\\t-1=0\qquad\text{add 1 to both sides}\\t=1\geq0\\\\t-8=0\qquad\text{add 8 to both sides}\\t=8\geq0$

$t=x^2\to x^2=1\ \vee\ x^2=8\\\\x^2=1\Rightarrow x=\pm\sqrt1\to x=\pm1\\\\x^2=8\Rightarrow x=\pm\sqrt8\to x=\pm\sqrt{4\cdot2}\to x=\pm\sqrt4\cdot\sqrt2\to x=\pm2\sqrt2$

4 0

3 years ago

Read 2 more answers

Select the functions that have a value of -1. sin180° cos180° tan180° csc180° sec180° cot180°

kupik [55]

We have to break each degree in terms of 90

A) $sin180^\circ=sin(90\times2+0)$

Which is in third quadrant, therefore sine is negative hence

$sin(90\times2+0)= -sin0 ^\circ = 0$

B) $cos180^\circ =cos(90\times2+0)$

Which is in third quadrant, therefore cosine is negative hence

$cos(90\times2+0)= -cos0^\circ = -1$

C) $tan180^\circ=tan(90\times2+0)$

Which is in third quadrant, therefore tangent is positive hence

$tan(90\times2+0)= tan0^\circ = 0$

D) $csc180^\circ=csc(90\times2+0)$

Which is in third quadrant, therefore cosec is negative hence

$cosec(90\times2+0)= -csc0^\circ =$ not defined

E) $sec180^\circ=sec(90\times2+0)$

Which is in third quadrant, therefore secant is negative hence

$sec(90\times2+0)= -sec0^\circ = -1$

F) $cot180^\circ=cot(90\times2+0)$

Which is in third quadrant, therefore tangent is positive hence

$cot(90\times2+0)= cot0^\circ =$ not defined

Hence only $cos 180^\circ$ and

$sec180^\circ$ have value -1

Hope this will help

7 0

3 years ago

If your starting salary were $40,000 and you received a 3% increase at the end of every year for 15 years, what would be the tot

Dmitry [639]

T = 40000 + 40000(1.03) + 40000(1.03)^2 + ... + 40000(1.03)^15

Multiply the above equation by 1.03 giving

1.03(T) = 40000(1.03) + 40000(1.03)^2 + 40000(1.03)^3 + ... + 40000(1.03)^15 + 40000(1.03)^16

Now subtract the first equation from the second to give

0.03T = 40000(1.03)^16 - 40000

0.03T = 40000(1.03^16 - 1)

0.03T = 24188.26

T = 24188.26 / 0.03 = $806275.25

6 0

4 years ago

Read 2 more answers