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IrinaVladis [17]
3 years ago
5

Slove for m m+7=3+m+4

Mathematics
1 answer:
ser-zykov [4K]3 years ago
4 0

Answer:

no solution

Step-by-step explanation:

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How do I solve this?:<br> 12x + 2 = 3x - 25
Dmitry_Shevchenko [17]
12x + 2 = 3x - 25. STEP 1) subtract 3x from 12x so it now is: 9x +2 = -25 STEP 2) subtract 2 from -25 so it now is: 9x = -27 STEP 3) divide each side by 9 so now it is: x = -3
3 0
4 years ago
Determine the range of the following graph:
Vlada [557]

Answer as an inequality:    \boldsymbol{2 \le y \le 7}

Answer in interval notation: [2, 7]

==========================================================

Explanation:

The range is the set of all possible y outputs of a function.

The lowest point occurs when y = 2

The highest point occurs when y = 7

The range is the set of every y value between 2 and 7, including the endpoints.

The range as an inequality is 2 \le y \le 7

It is equivalent to [2, 7] in interval notation. The square brackets include each endpoint.

7 0
3 years ago
A furniture store had a chair that cost $33. After a few months the owner took 12 percent off the price. How much is the chair n
zhannawk [14.2K]

Answer:

$29.04

Step-by-step explanation:

5 0
4 years ago
Read 2 more answers
Find csc(angle) if tan(angle) = -4/3 and sin(angle) is positive.
Lerok [7]

Answer:

hm?

Step-by-step explanation:

hm

7 0
3 years ago
A student makes a sign out of a rectangular piece of cardboard for an upcoming event at school. The piece of cardboard has a len
seraphim [82]

Answer:

915 in²

Step-by-step explanation:

The area of the rectangle :

Length = 32 inches

Width = 25 - (10+10) = 25 - 20 = 5 inches

Area of rectangle = Length * width

Area = 32 * 5 = 160 in²

Area of triangle :

Base = 25 inches

Height = (46 - 32) inches = 14 inches

Area of triangle = 1/2 * base * height

Area of triangle = 1/2 * 25 * 14 = 175 in²

Total area = (160 + 175)in² = 335 in²

Total area of cardboard :

50 inches * 25 inches = 1250 in²

Amount of cardboard not used :

(1250 - 335) in² = 915 in²

3 0
3 years ago
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