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3 years ago

D is going in the 4th quadrant. Please help

Mathematics

1 answer:

dangina [55]3 years ago

8 0

What are you asking here? Are you asking if D is the right answer? If so then I can’t see D.

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Pls help it’s due tn

OverLord2011 [107]

Answer:

94 for the first one and 130 for the second

Step-by-step explanation:

Since A=6 and B=4

For the first one

13(6)+ 4(4)

78+16=94

For the second one

(6+4)*13

(10)*13= 130

8 0

3 years ago

Can u answer this please?

denpristay [2]

2. 2 increasing
3. Y=-x +9 decreasing
4. 2 increasing
5. 6 increasing
6. Y=-3x+1 decreasing

5 0

2 years ago

Two trains begin in Milford and end in Pinkerton, which is 300 miles away. Train A leaves Milford at 10:00 a.M. And travels at a

cluponka [151]

Answer:

B. Train B

Step-by-step explanation:

We are told that Milford and Pinkerton is 300 miles away.

Train A leaves Milford at 10:00 am. There are 3 hours between 10:00 am to 1:00 pm. So let us find distance traveled by train A in 3 hours.

$\text{Distance}=\text{Speed*Time}$

$\text{Distance traveled by train A}=90\frac{\text{ miles}}{\text{ hour}}\times 3\text{ hours}$

$\text{Distance traveled by train A}=90\times 3{\text{ miles}$

$\text{Distance traveled by train A}=270{\text{ miles}$

Since train A will cover 270 miles in 3 hours and distance between Milford and Pinkerton is 300 miles, therefore, train A will not arrive Pinkerton before 1:00 pm.

Since there are 5 hours between 8:00 am to 1:00 pm, so let us find distance traveled by train B in 5 hours.

$\text{Distance traveled by train B}=70\frac{\text{ miles}}{\text{ hour}}\times 5\text{ hours}$

$\text{Distance traveled by train B}=70\times 5 \text{ miles}$

$\text{Distance traveled by train B}=350\text{ miles}$

Since train B will cover 350 miles in 5 hours, therefore, train B will arrive Pinkerton before 1:00 pm and option B is the correct choice.

5 0

4 years ago

Need help with a simple problem 2^x=3^x+1

KiRa [710]

For $x\ \textgreater \ 0$ , $2^x\ \textless \ 3^x$ , all the more $2^x\ \textless \ 3^x+1$ , therefore no solution.

For $x=0$ , we have $2^0=3^0+1 \Rightarrow 1=1+1 \Rightarrow 1=2$ . Obviously that' false.

For $x\ \textless \ 0$ both $2^x$ and $3^x$ , where $2^x\ \textgreater \ 3^x$ , belong to the range $(0,1)$ , then $3^x+1$ belong to the range $(1,2)$ .
Those ranges don't have a common part, therefore, again, no solution.

So, the equation $2^x=3^x+1$ doesn't have a solution.

4 0

3 years ago

Determine the slope and intercept of each graph. Then, write the equation of the graph in slope-intercept form

RoseWind [281]

Answer:

Slope= -1,2

Y-Int=(0,-1)

Equation= Y=-1/2x-1

Step-by-step explanation:

7 0

3 years ago