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Oksanka [162]
3 years ago
7

Suppose u · v = 0. Which vectors could represent u and v?

Mathematics
2 answers:
eduard3 years ago
5 0

Answer: A. u = ⟨3, 4⟩ and v = ⟨4, –3⟩

Step-by-step explanation:

edge2020

Schach [20]3 years ago
4 0

Answer:

a

Step-by-step explanation:

edge 2020

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What is the number that when you multiply by six and subtract four to the product you get 32
Furkat [3]

Answer:

6

Step-by-step explanation:

32 + 4 = 36

36 / 6 = 6

3 0
3 years ago
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Barbara bought 5 movie tickets for $30. If she bought 9 tickets how much would it cost?
Mamont248 [21]
$54
30 divided by 5 is 6. then 6 times 9 is 54
4 0
3 years ago
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lvava is calculating the area of a circle with a radius of 3/4 which of the following gives the BEST estimation of the area?
STALIN [3.7K]

Answer:

28.274

Step-by-step explanation:

8 0
3 years ago
A number line is numbered in tenths. Describe where you would plot 87.35 squared.
mezya [45]

Answer:

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Step-by-step explanation:

please show a picture of the problem.

3 0
3 years ago
In April, Phillipa rode 13 . 5 + 8 . 7 + 11 . 1 miles on her bicycle. In March, she rode ( 13 . 5 + 8 . 7 + 11 . 1 ) ÷ 2 miles,
bonufazy [111]

Answer:

Phillipa rode the most in May and rode the least in March.

Distance travelled by Phillipa on her cycle in May = 8 × Distance travelled by Phillipa on her cycle in March  

Step-by-step explanation:

Given:

In April, Phillipa rode 13 . 5 + 8 . 7 + 11 . 1 miles on her bicycle. In March, she rode ( 13 . 5 + 8 . 7 + 11 . 1 ) ÷ 2 miles, and in May, she rode 4 × ( 13 . 5 + 8 . 7 + 11 . 1 ) miles.

To find: the month when she rode the most and the month when she rode the least

Solution:

Distance travelled by Phillipa on her cycle in April = 13 . 5 + 8 . 7 + 11 . 1 = 65 + 56 + 11 = 132 miles

Distance travelled by Phillipa on her cycle in March = ( 13 . 5 + 8 . 7 + 11 . 1 ) ÷ 2 = \frac{132}{2}=66 miles

Distance travelled by Phillipa on her cycle in May = 4 × ( 13 . 5 + 8 . 7 + 11 . 1 ) = 4 × 132 = 528 miles

So, she rode the most in May and rode the least in March

Distance travelled by Phillipa on her cycle in May = 8 × Distance travelled by Phillipa on her cycle in March  

8 0
3 years ago
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