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Westkost [7]
3 years ago
11

8x^2+1/9

Mathematics
1 answer:
umka2103 [35]3 years ago
5 0

Answer:

A. Quartic

Step-by-step explanation:

I went to desmos graphing,

8x^2+1/9 (plug it in and looked at the line)

It shows a parabola,

y-intercept: (0,0.111)

"Cubic functions. Three points not in a line determine a parabola, a polynomial function of degree 2. Polynomials of degree 2 are quadratic functions. Their graphs are parabolas."

Therefore, this is a quadratic ( quartic) since the degree in this parabola is 2.

You might be interested in
Round $38.09 to the nearest dollar<br> $38<br> $40<br> $30<br> $39
Veronika [31]

Answer:

$38

Step-by-step explanation:

Since the last two numbers aren't over 50, we would round down. This leaves you with $38.

7 0
3 years ago
What value of x makes this inequality true? <br> x + 16 &lt; 43
lianna [129]

Answer:

x < 27

Step-by-step explanation:

x + 16 < 43

move the constant to the right-hand side and change its sign

x < 43 - 16

subtract the numbers

x < 27

~~~~~~~~~~~~~~~~~~

X < 27

alternative form

X ∈ ( - ∞ , 27 ) , { x | x < 27 }

5 0
3 years ago
Thanks for the help!
NikAS [45]

Answer:

A

Step-by-step explanation:

So we have the piecewise function:

f(x)= \begin{cases}\sqrt{2x} & \text{if }x

And we want to find f(8).

Since our input value is 8, choose the equation that fits our input.

The first equation demand x to be less than 3. 8 is not less than 3, so we won't use that.

The second equation demand x to e greater than or equal to 3 and less than 8. 8 is <em>not</em> less than 8. So, we won't use that.

The third equation demands x to be greater than or equal to 8. 8 is greater than or equal to 8, so we'll use the third equation.

So:

f(x)=42\text{ if }x\geq 8

f(8)=42

There're nothing more to do, we're done :)

The answer is A.

Edit: Improved Format

3 0
4 years ago
Someone help me its timed!!!
Lelechka [254]

Answer:

C!

Step-by-step explanation:

7 0
3 years ago
The smallest prime number that is a foctor of 15
GrogVix [38]
The factors of 15 are 1, 3, 5 and 15. Now, as 1 is neither prime and nor a composite number (1 is not Prime because for a number to be a prime, it should have exact 2 factors i.e. 1 and itself, but 1 has only one factor. Therefore 1 is not prime.)

So the smallest prime factor of 15 is 3.

Hope this helped! :)
6 0
3 years ago
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