First we'll substitute
with 

Then we can separate this.

Then we'll solve this.



Then we'll plug in to find the extraneous solutions (if any)

Answer: we dont have options
Step-by-step explanation:
- cos ( 1/2 x + 1/5 π ) = 0 ( and because if cos α = 0, α= π/2 + k π, k ∈ Z )
1/2 x + π/5 = π/2 + k π, k ∈ Z
1/2 x = π/2 - π/5 + k π / * 2
x = π - 2π/5 + 2 k π
x = 3/5 π + 2 k π = 0.6 π + 2 k π
Answer:
If k = 0: x 1 = 0.6 π = 3π/5
k = 1 : x 2 = 2.6 π = 13π/5
Answer:
20
Step-by-step explanation:
Answer:
Vertical Asymptote:

Horizontal asymptote:
it does not exist
Step-by-step explanation:
we are given

Vertical asymptote:
we know that vertical asymptotes are values of x where f(x) becomes +inf or -inf
we know that any log becomes -inf when value inside log is zero
so, we can set value inside log to zero
and then we can solve for x

we get

Horizontal asymptote:
we know that
horizontal asymptote is a value of y when x is +inf or -inf
For finding horizontal asymptote , we find lim x-->inf or -inf



so, it does not exist