I don’t know what 12 divided by 6

<img src="https://tex.z-dn.net/?f=%20%7B8%7D%5E%7B2%7D%20%20%3D%2030%20%5Ctimes%2043x" id="TexFormula1" title=" {8}^{2} = 30 \t

Anarel [89]

Answer:

Step-by-step explanation:

8² = 30 * 43x

x = 8² / 30 * 43 = 8* 8 / 30*43

= 2*2*2 * 2*2*2 / 3*2*5*43

=2*2*2*2*2/ 3*5*43

= 32/645

5 0

3 years ago

Free points: this is because of all the kindness I have seen on brainly:

yarga [219]

Answer:

Step-by-step explanation:

4 0

3 years ago

In a class 27 of students, 12 have a cat and 11 have a dog. There are 5 students who have a cat and a dog. What is the probabili

frosja888 [35]

Answer:

41.67% probability that a student has a dog given that they have a cat

Step-by-step explanation:

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: having a cat.

Event B: having a dog.

12 of 27 students have a cat:

This means that $P(A) = \frac{12}{27}$

5 students who have a cat and a dog.

This means that $P(A \cap B) = \frac{5}{27}$

What is the probability that a student has a dog given that they have a cat?

$P(B|A) = \frac{\frac{5}{27}}{\frac{12}{27}} = \frac{5}{12} = 0.4167$

41.67% probability that a student has a dog given that they have a cat

6 0

4 years ago

Consider the polynomials p(x) = 3x + 27x^2 and q(x)= 2 . Find the x -coordinate(s) of the point(s) of intersection of these two

Tom [10]

Answer:

The x -coordinate(s) of the point(s) of intersection of these two polynomials are $x=\frac{2}{9}\approx0.2222,\:x=-\frac{1}{3}\approx-0.3333$

The sum of these x -coordinates is $\frac{2}{9}+\left(-\frac{1}{3}\right)=-\frac{1}{9}$

Step-by-step explanation:

The intersections of the two polynomials, p(x) and q(x), are the roots of the equation p(x) = q(x).

Thus, $3x + 27x^2=2$ and we solve for x

$3x+27x^2-2=2-2\\27x^2+3x-2=0\\\left(27x^2-6x\right)+\left(9x-2\right)\\3x\left(9x-2\right)+\left(9x-2\right)\\\left(9x-2\right)\left(3x+1\right)=0$

Using Zero Factor Theorem: = 0 if and only if = 0 or = 0

$9x-2=0\\9x=2\\x=\frac{2}{9}$

$3x+1=0\\3x=-1\\x=-\frac{1}{3}$

The solutions are:

$x=\frac{2}{9}\approx0.2222,\:x=-\frac{1}{3}\approx-0.3333$

The sum of these x -coordinates is

$\frac{2}{9}+\left(-\frac{1}{3}\right)=-\frac{1}{9}$

We can check our work with the graph of the two polynomials.

4 0

4 years ago

You have deposited $800 in a savings account, which pays three percent interest compounded quarterly. Find the amount in the acc

madreJ [45]

$928.95
You take $800 and multiply it by 0.0075 which is 1/4 of 3% since there are 4 quarters per year. Every time you multiply it you add the previous number and you have to do this 20 times since there are 20 quarters in 5 years. For example, 800 x 0.0075 = 6 + 800 = 806 x 0.0075 = 6.045 + 806 = 812.045 x <span>0.0075 = 6.0903375 + 812.045 = 818.1353375 and you just keep doing thing until you reach your total amount of quarters. Then you just round your decimal point to the hundredth place.</span>

3 0

3 years ago