The equation of a line passing through point (4, -1) and perpendicular to the line whose equation is 2x - y - 7 = 0 is y = -1/2x + 1
<h3>Equation of a line</h3>
A line is the shortest distance between two points. The equation of a line in point-slope form and perpendicular to a line is given as;
y - y1 = -1/m(x-x1)
where
m is the slope
(x1, y1) is the intercept
Given the following
Point = (4, -1)
Line: 2x-y - 7 = 0
Determine the slope
-y = -2x + 7
y= 2x - 7
Slope = 2
Substitute
y+1 = -1/2(x -4)
Write in slope-intercept form
2(y + 1) = -(x - 4)
2y+2 = -x + 4
2y = -x + 2
y = -1/2 + 1
Hence the equation of a line passing through point (4, -1) and perpendicular to the line whose equation is 2x - y - 7 = 0 is y = -1/2x + 1
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Answer:
(0, 11) is a solution.
(8, 12) is a solution.
(16, 13) is a solution
(1, 89/8)
(2, 45/4)
Step-by-step explanation:
y = 1/8x + 11
for this equation....
y = (1/8) x + 11
let x = 0 get
y = 0 + 11 = 11
(0, 11) is a solution.
(8, 12) is a solution.
(16, 13) is a solution
(1, 89/8) because y = 1/8 + 11 = 1/8 + 88/8 = 89/8
(2, 45/4)
2(4y+1) = 3y. We need to solve for y.
First let's get ride of the parenthesis by developing 2(4y+1). This means to multiply 2 by 4y and 2 by 1, and add them.
2(4y+1) = 2*4y + 2*1 = 8y + 2
So 2(4y+1)=3y
8y+2 = 3y
Then you subtract 8y from each side to have the variables on a side and the numbers on the other:
3y - 8y = 8y + 2 - 8y
-5y = 2
Then you divide each side by -5 to get the variable y alone on a side and its value on the other:
(-5y)/-5 = 2/-5
y = -2/5
You can re-check your answer (very important):
2(4y + 1) = 2(4*-2/5 + 1) = -1.2
3y = 3 * -2/5 = -1.2
So 2(4y+1)=3y= -1.2
The answer has been approved.
Hope this Helps! :)
Answer:
0.00305 (rounded)
Step-by-step explanation:
this is a geometric sequence so the formula is
an=a×r×n-1