The box plot shows the time it takes you and your classmates to get to school. What is the median time spent traveling to school
?
A.) 6 minutes
B.) 12 minutes
C.) 16 minutes
D.) 24 minutes
A.) 6 minutes
B.) 12 minutes
C.) 16 minutes
D.) 24 minutes
1 answer:
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Solution :
The formula for the linearization of a function at a point
= a is given as
Assuming the time is t and the distance travelled is , that makes the speed as
.
So substituting them in the linearization formula,
A. At t = 7 minutes
f(7) = 2.5 km
f'(7) = 0.5 kpm
∴
B. At t = 18 minutes
f(18) = 14.8 km
f'(18) = 0.8 kpm
∴
C. Substituting the value of t as 14 in both the linearization to determine the position at 14 minutes, we get
= 7 - 1
= 6 km
= 11.2 + 0.4
= 11.6 km
D. According to the linearization at 7, the distance travelled between the 7 minutes and 14 minutes is = 6 km - 2.5 km
= 3.5 km
And between the 14 minutes and 18 minutes is = 14.8 km - 6 km
= 8.8 km
This is an average speed of 0.5 kpm in the first interval and an average speed of 2.2 kpm.
Now, according to the linearization of 18, the distance travelled between the 7 minutes and the 14 minutes is = 11.6 km - 2.5 km
= 9.1 km
And between 14 minutes and 18 minutes is = 14.8 km - 11.6 km
= 3.2 km
This gives an average speed of 1.3 kpm in the first interval and 0.8 kpm in the second interval.
Therefore, the second approximation is the better one since the average speed are closer to the actual readings in the second linearization.
<em>The function uses W as the variable but the options show only x's as the variable, so I'm asumming W in the answer</em>
Answer:
0 < W < 50
Correct option: A
Step-by-step explanation:
<u>Domain of functions</u>
Some functions have restricted values of the independent variable x. It can be due to mathematical restrictions, like dividing by 0 or taking the square root of a negative number, of it can be due to practical conditions of the situation being modeled.
In this case, the area of a rectangle is given by the quadratic function.
Since the area of a rectangle cannot be negative (and should be positive, though it could be zero), the practical domain of A is determined when
Taking common factor W
Since W must be positive W>0
Or equivalently
The total interval is
Correct option: A
Please note: The real restriction should be
if we allowed the area to be positive, but I'm providing the most possible correct available option