Tan (Ф/2)=⁺₋√[(1-cosФ)/(1+cosФ)]
if π<Ф<3π/2;
then, Where is Ф/2??
π/2<Ф/2<3π/4; therefore Ф/2 is in the second quadrant; then tan (Ф/2) will have a negative value.
tan(Ф/2)=-√[(1-cosФ)/(1+cosФ)]
Now, we have to find the value of cos Ф.
tan (Ф)=4/3
1+tan²Ф=sec²Ф
1+(4/3)²=sec²Ф
sec²Ф=1+16/9
sec²Ф=(9+16)/9
sec²Ф=25/9
sec Ф=-√(25/9) (sec²Ф will have a negative value, because Ф is in the sec Ф=-5/3 third quadrant).
cos Ф=1/sec Ф
cos Ф=1/(-5/3)
cos Ф=-3/5
Therefore:
tan(Ф/2)=-√[(1-cosФ)/(1+cosФ)]
tan(Ф/2)=-√[(1+3/5)/(1-3/5)]
tan(Ф/2)=-√[(8/5)/(2/5)]
tan(Ф/2)=-√4
tan(Ф/2)=-2
Answer: tan (Ф/2)=-2; when tan (Ф)=4/3
The 3rd answer, when m is next to a number it means “per” for something like per second or (in this case) per minute, etc...
9514 1404 393
Answer:
12 square inches
Step-by-step explanation:
The area is given by the formula ...
A = 1/2bh
Here, the base is 6 inches and the height is given as 4 inches. Then the area is ...
A = (1/2)(6 in)(4 in) = 12 in²
The area of the triangle is 12 square inches.
_____
<em>Comment on the problem</em>
Since you are given the base and height, we presume you are intended to use the formula above. You are also given all three side lengths. If you use the appropriate formula with those, you find the area is about 15.6 square inches. (The height of this triangle is actually closer to 5.2 inches.)
The figure represents a geometry that cannot exist. With the given base and height, the side lengths should be 5, not 6.
Step-by-step explanation:
The T-shirt is launched with an initial upward velocity of 60 ft/s from a height of 5 feet. Its equation of motion is given by :
....(1)
(a) For maximum height, put 
So,
Now put,
So, the time taken for the T-shirt to reach maximum height is 2.5 seconds.
(b) Put x = 2.5 s in equation (1)
Answer: year 2194
Explanation:
1) Model the jump of the women:
i) initial jump = 70.0 in
ii) increase rate = 0.48% per year
iii) equation: h = 70.0(1 +0.0048)ⁿ
2) Model the jump of the men:
i) initial jump 86.5 inches.
ii) increase rate, 0.4%.
iii) equation: h = 86.5 (1 + 0.004)ⁿ
3) Equal the two equations (h = h) to find when the jumps will be equal:
i) 70.0(1 +0.0048)ⁿ = 86.5 (1 + 0.004)ⁿ
ii) 70.0(1.0048)ⁿ = 86.5 (1.004)ⁿ
ii) [1.0048ⁿ / 1.004ⁿ] = 86.5/70.0
iii) [1.0048/ 1.0040]ⁿ = 86.5/70.0
iv) n log (1.0048 / 1.0040) = log ( 86.5/70)
v) n = log (86.5/70) / log (1.0048/1.0040) ≈ 266
3) year = 1928 + 266 = 2194
That is in the year 2194
