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babunello [35]
3 years ago
6

Find the length of the arc.

Mathematics
1 answer:
Marizza181 [45]3 years ago
6 0

Answer:

1st option

Step-by-step explanation:

The length of the arc is calculated as

arc = circumference of circle × fraction of circle

      = 2πr × \frac{210}{360}

      = 2π × 13 × \frac{21}{36}

      = 26π × \frac{7}{12}

      = \frac{26\pi (7)}{12}

      = \frac{182\pi }{12}

      = \frac{91\pi }{6}

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Given the Arithmetic sequence A1,A2,A3,A4 28, 33, 38, 43 What is the value of A11?
harkovskaia [24]
28,33,38,43

the common difference can be found by subtracting the first term from the second term.....33 - 28 = 5....so the common difference (d) = 5

an = a1 + (n - 1) * d
n = the term u want to find = 11
a1 = first term = 28
d = common difference = 5
now we sub
a11 = 28 + (11 - 1) * 5
a11 = 28 + 10 * 5
a11 = 28 + 50
a11 = 78
7 0
4 years ago
Read 2 more answers
Find, then state if it’s a function
valentina_108 [34]

Answer:

The answer is y = ± \sqrt[4]{\frac{x}{4}} ,  f^{-1}(x) is a function ⇒ 1st answer

Step-by-step explanation:

Let us revise the steps of find the inverse of a function

  1. Replace f(x) with y
  2. Replace every x by y and replace y by x
  3. Solve the equation in Step 2 for y
  4. Replace y by f^{-1}(x)

∵ f(x)=4x^{4}

- Replace f(x) by y

∴ y=4x^{4}

- Replace y by x and x by y

∴ x=4y^{4}

- Divide each side by 4

∴ \frac{x}{4}=y^{4}

- Take \sqrt[4]{}  for both sides

∴ ± \sqrt[4]{\frac{x}{4}}=y

- Switch the two sides

∴ y = ± \sqrt[4]{\frac{x}{4}}

∵ There is no fourth root for negative number

∴ x ≥ 0

When you test the graph of f^{-1}(x) by a vertical line, it will cut it just at one in every position, so it is a function. Look to the attached graph for more understand

∴  f^{-1}(x) is a function

The answer is y = ± \sqrt[4]{\frac{x}{4}} ,  f^{-1}(x) is a function

8 0
3 years ago
The sum of two binomials is 5x^2-6x . If one of the binomials is3x^2-2x , what is the other binomial?
vlada-n [284]
Its 2x^2-4x, to check it add it to 3x^2-2x or
2x^(2)-4x+3x^(2)-2x
6 0
4 years ago
Please Help Me !!!!!!
son4ous [18]
1.\\(4x^2+15x-3)-(-3x^2+5)\\=4x^2+15x-3+3x^2-5\\=7x^2+15x-8\leftarrow A.


2.\\-3f^2+4f-3+8f^2+7f+1\\=5f^2+11f-2\leftarrow C.


3.\\(2x^2+6x+1)+(-7x^2+2x-3)\\=2x^2+6x+1-7x^2+2x-3\\=-5x^2+8x-2\leftarrow B.


4.\\4x^2+3x-3\\\{4;\ 3;-3\}


5.\\6x^4+3x^3-2x^2+15x-14\\\{6;\ 3;-2;\ 15;-14\}\to5\leftarrow A.


6.\\-7x-5x^2+5\\\{-7\}\leftarrow D.


7.\\(2.5\cdot10^4)(4\cdot10^3)=2.5\cdot4\cdot10^{4+3}=10\cdot10^7\\=10^{1+7}=10^8=1\cdot10^8\leftarrow C.


8.\\2^2\cdot2^8=2^{2+8}=2^{10}\leftarrow B.
3 0
3 years ago
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2 by root3 + root 2 + 1​
Zepler [3.9K]

Answer:

tyrnnnnnfjj

Step-by-step explanation:

7 0
3 years ago
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