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2 years ago

Write a paragraph describing how basketball and ultimate frisbee are similar. Include at least 5 ways.

2 answers:

4 0

The only difference between ultimate Frisbee and basketball is the equipment; instead of using a ball, a disc is used; however, either way it is the same concept. ... The premise of this game is to pass the ball into the opposing team's endzone and score the most points.

BartSMP [9]2 years ago

4 0

Answer:

both include shooting accuracy

both can be done outdoors

both have to be thrown into some type of goal to score points

both require practice to be good

both involve throwing of some sort

Step-by-step explanation:

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Which graph best represents the solution to 1/2x - 2 = 3

inysia [295]

Answer:

The one showing only the point (10, 3)

Or the linear plot with the point +10 highlighted.

Step-by-step explanation:

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2 years ago

3 ears of corn cost $1

lisov135 [29]

Yes 3 ears of corn cost $1

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2 years ago

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Explain how you can tell that the equation, description, graph, and table all represent the same situation.

andrew-mc [135]

Answer:think of many situations you can come up with or problems you can solve which will end up with the same answer if u use different methods

Step-by-step explanation:

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2 years ago

Solve the 3 × 3 system shown below. Enter the values of x, y, and z. X + 2y – z = –3 (1) 2x – y + z = 5 (2) x – y + z = 4 (3)

Svet_ta [14]

<h2>Answer:</h2>

$\boxed{x=1, \y=-1, \ z=2}$

<h2>Step-by-step explanation:</h2>

We will use the Gaussian elimination method to solve this problem. To do so, let's follow the following steps:

Step 1: Let's multiply first equation by −2. Next, add the result to the second equation. So:

$\begin{array}{ cccc }~~ x&+~~2~ y&-~~~~~ z&~=~-3\\&-~~~5~ y&+~~3~ z&~=~11\\~~ x&-~~~~~ y&+~~~~ z&~=~4\end{array}$

Step 2: Let's multiply first equation by −1. Next, add the result to the third equation. Thus:

$\begin{array}{ cccc }~~ x&+~~2~ y&-~~~~~ z&~=~-3\\&-~~~5~ y&+~~3~ z&~=~11\\&-~~~3~ y&+~~2~ z&~=~7\end{array}$

Step 3: Let's multiply second equation by −35, Next, add the result to the third equation. Therefore:

$\begin{array}{ cccc }~~ x&+~~2~ y&-~~~~~ z&~=~-3\\&-~~~5~ y&+~~3~ z&~=~11\\&&+~~\frac{ 1 }{ 5 }~ z&~=~\frac{ 2 }{ 5 }\end{array}$

Step 4: solve for z, then for y, then for x:

$\frac{ 1 }{ 5 } ~ z & = \frac{ 2 }{ 5 } \\ \\ \boxed{z & = 2}$

$-5y+3z &= 11\\-5y+3\cdot 2 &= 11\\ \\ \boxed{y &= -1}$

By substituting $y=-1 \ and \ z=2$ into the first equation, we get the $x$ . So:

$x+2(-1)-2=-3 \\ \\ x-2-2=-3 \\ \\ \boxed{x=1}$

6 0

3 years ago

Read 2 more answers

Hi I would like to know how I can solve this problem.

murzikaleks [220]

The $n$ -th term is

$U_n = \dfrac14 n^2 (n+1)^2$

so the 39th term is

$U_{39} = \dfrac14 39^2 40^2 = \boxed{608,400}$

Observe that

$2^3 + 4^3 + 6^3 = 2^3 + 2^3\times2^3 + 2^3\times3^3 = 8\left(1^3+2^3+3^3)$

which suggests that

$V_n = 8U_n = \boxed{2n^2(n+1)^2}$

3 0

1 year ago