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mariarad [96]
3 years ago
5

Consider the following triangle.

Mathematics
2 answers:
egoroff_w [7]3 years ago
7 0

Answer: C

Step-by-step explanation:

U have to add the numbers up. Then times it by 2/3 and 1/3 to see if the same numbers are on ur screen.

12345 [234]3 years ago
7 0

Answer:

c

Step-by-step explanation:

You might be interested in
Express x in terms of y! Find the value of x when y =5<br>2(x - 3)/y =5​
m_a_m_a [10]

Hey there!

2(x - 3) / y = 5

2(x - 3) / 5 = 5

2(x) + 2(-3) / 5 = 5

(2x - 6) 5 = 5

MULTPLY 5 to BOTH SIDES

(2x - 6)/5 * 5 = 5 * 5

SIMPLIFY IT!
2x - 6 = 5 * 5

2x - 6 = 25

ADD 6 to BOTH SIDES

2x - 6 + 6 = 25 + 6

SIMPLIFY IT!
2x = 25 + 6

2x = 31

DIVIDE 2 to BOTH SIDES

2x/2 = 31/2

SIMPLIFY IT!

x = 31/2

x = 15 1/2


Therefore, the answer should be:

x = 15 1/2


Good luck on your assignment & enjoy your day!



~Amphitrite1040:)

5 0
2 years ago
Read 2 more answers
C is the midpoint of line segment AB Find the value of x, if line segment AB = 5x and line segment AC = 20.
Softa [21]
D.8

A and C are out because they would get you ether lower or equal to 20, which is equal to AC and your trying to find X in AB which is so posed to be the what equals AC+BC.
AB=AC+BC
5x=20+BC
5(8)=20+BC
40=20+BC
40=20+20

AC equals 20. AB will have to equal AC+ CB. If you put in A.4 in AB 5X you will get twenty and that not what you want. You want to get a number that will get you the an answer greater to AC. So 5(8)=40. 
5 0
3 years ago
Consider a value to be significantly low if its z score less than or equal to minus−2 or consider a value to be significantly hi
ziro4ka [17]

Answer:

If the weight is higher than 5.8886 gr would be considered significantly high

If the weight is lower than 5.6121 gr would be considered significantly low

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the weights of a population, and for this case we know the distribution for X is given by:

X \sim N(5.75241,0.06281)  

Where \mu=5.75241 and \sigma=0.06281

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

For the case when z =-2 we can do this:

-2 = \frac{X-5.75241}{0.06281}

And if we solve for X we got:

X = 5.75241 -2*0.06281 =5.6121

And for the other case when Z=2 we have:

2 = \frac{X-5.75241}{0.06281}

And if we solve for X we got:

X = 5.75241 +2*0.06281 =5.8886

If the weight is higher than 5.8886 gr would be considered significantly high

If the weight is lower than 5.6121 gr would be considered significantly low

5 0
3 years ago
Please Do 3 for 5 points.
alukav5142 [94]

Answer:

44, 46, and 48

Step-by-step explanation:

add them and you should get 138.

7 0
3 years ago
Plz help me im timed i need help​
Fittoniya [83]

Answer:

Step-by-step explanation:

Its x= 30

8 0
3 years ago
Read 2 more answers
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