(a)
since 13 is prime.
(b)
, and there are 81/3 = 27 multiples of 3 between 1 and 81, which leaves 81 - 27 = 54 numbers between 1 and 81 that are coprime to 81, so
.
(c)
; there are 50 multiples of 2, and 20 multiples of 5, between 1 and 100; 10 of these are counted twice (the multiples of 2*5=10), so a total of 50 + 20 - 10 = 60 distinct numbers not coprime to 100, leaving us with
.
(d)
; there are 51 multiples of 2, 34 multiples of 3, and 6 multiples of 17, between 1 and 102. Among these, we double-count 17 multiples of 2*3=6, 3 multiples of 2*17=34, and 2 multiples of 3*17=51; we also triple-count 1 number, 2*3*17=102. There are then 51 + 34 + 6 - (17 + 3 + 2) + 1 = 70 numbers between 1 and 102 that are not coprime to 102, and so
.
Answer:
127/12
Step-by-step explanation:
4 × 2 + 12x = 135
(1. Simplify 4 x 2 to 8.
8 + 12x = 135
(2. Subtract 88 from both sides.
12x= 135 - 8
(3. Simplify 135 - 8 to 127
12x = 127
(4. Divide both sides by 12
x= 127/12
Decimal Form: 10.583333
I think this is the awnser, but don't quote me on that
Answer:
A-B
Step-by-step explanation:
DONT look at that photo. You have no idea what's in that link!
The answer is d) 6 batteries
Answer:

General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Algebra I</u>
<u>Algebra II</u>
- Distance Formula:

Step-by-step explanation:
*Note:
The distance formula is derived from the Pythagorean Theorem.
<u>Step 1: Define</u>
<em>Identify</em>
Point (5, 10)
Point (10, 12)
<u>Step 2: Find distance </u><em><u>d</u></em>
- Substitute in points [Distance Formula]:

- [√Radical] (Parenthesis) Subtract:

- [√Radical] Evaluate exponents:

- [√Radical] Add:
