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Thepotemich [5.8K]
3 years ago
15

Given 1,000 inches, how many feet are there?

Mathematics
2 answers:
MAVERICK [17]3 years ago
6 0

Answer:

1000 inches / 12

=83.33... feet

bonufazy [111]3 years ago
5 0

Answer:

83.3333 feet

Step-by-step explanation:

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What is the value of x in the equation<br> 0, when y = 15?<br> 4.
Tatiana [17]

Answer:

x =200

Step-by-step explanation:

\frac{1}{5}x - \frac{2}{3}(15) =30\\\\\frac{1}{5}x-10=30\\\\\frac{1}{5}x=30+10\\\\\frac{1}{5}x=40\\\\x = 40*5\\x= 200

8 0
3 years ago
The graph of g(x), shown is a vertical shift of the graph of f(x)=2^x. Write the equation for g(x)
DaniilM [7]

Answer:

It's D .

Step-by-step explanation:

The graph of  f(x) = 2^x passes through the y axis at (0, 1).

The graph of g(x) passes through (0, 0) so g(x) = 2^x - 1.

4 0
3 years ago
Read 2 more answers
A triangular pyramid has a volume of 333 and one-third yards cubed. What are the possible measures of the area of the base, B, a
FrozenT [24]

To find the option that satisfies the volume of the triangle, we can solve each option.

Formula for the volume a triangular prism: V = 1/3bh

Option A:

B = 50 centimeters squared; h = 10 centimeters

V = 1/3(50)(10)

V = 1/3(500)

V = 166.666... or 166 2/3 yards.

Therefore, this option is incorrect.

Option B:

B = 50 centimeters squared; h = 30 centimeters

V = 1/3(50)(30)

V = 1/3(1500)

V = 500 yards.

Therefore, this option is incorrect.

Option C:

B = 100 centimeters squared; h = 10 centimeters

V = 1/3(100)(10)

V = 1/3(1000)

V = 333.333... or 333 1/3 yards.

Therefore, this option is correct.

Option D:

B = 100 centimeters squared; h = 30 centimeters

V = 1/3(100)(30)

V = 1/3(3000)

V = 1000 yards.

Therefore, this option is incorrect.

Hence, the correct answer is [ B = 100 centimeters squared; h = 10 centimeters ]

Best of Luck!

6 0
3 years ago
Is 153 divisible by 3
Ne4ueva [31]

Answer:

Yes it 51

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Solve sin^4(x)+cos^4(x)=cos4x
ICE Princess25 [194]
\sin^4x=(\sin^2x)^2=\left(\dfrac{1-\cos2x}2\right)^2=\dfrac{1-2\cos2x+\cos^22x}4
\cos^4x=(\cos^2x)^2=\left(\dfrac{1+\cos2x}2\right)^2=\dfrac{1+2\cos2x+\cos^22x}4

\implies \sin^4x+\cos^4x=\dfrac{2+2\cos^22x}4=\dfrac{1+\cos^22x}2

\cos^22x=\dfrac{1+\cos4x}2
\implies\sin^4x+\cos^4x=\dfrac{1+\frac{1+\cos4x}2}2=\dfrac{3+\cos4x}4

So the equation reduces to

\dfrac{3+\cos4x}4=\cos4x
\dfrac34=\dfrac34\cos4x
\cos4x=1

We have \cos\theta=1 whenever \theta=0+2k\pi=2k\pi, where k is any integer. This means for this equation we have solutions at

4x=2k\pi\implies x=\dfrac{k\pi}2
6 0
4 years ago
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