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Tems11 [23]
3 years ago
11

Help and I’ll kiss u again mwah mwah

Mathematics
2 answers:
ElenaW [278]3 years ago
8 0

Answer:

It was reflected down and to the right I think.

Step-by-step explanation:

geniusboy [140]3 years ago
8 0

Answer:

tell me why ain't nothing but a heartache

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PLS HELP!! WILL GIVE BRAINLIEST!
Elodia [21]

Answer:

The lower quartile of Class A is greater than the lower quartile of Class B.

Class A has a Greater number of lower quartiles then Class B as the imagie shows. Class A has 65-75 while class B has 70-75.

3 0
3 years ago
Write the prime factorization for 168
11Alexandr11 [23.1K]
168|2\\.\ 84|2\\.\ 42|2\\.\ 21|3\\.\ \ 7|7\\.\ \ 1|\\\\168=2\cdot2\cdot2\cdot3\cdot7
7 0
4 years ago
-8(x + 1) + 3(x - 2) = -3x + 2?
alexira [117]
First you need to distribute the -8
So you would get -8x-8 now distribute the 3 so it would be 3x-6
-8x-8+3x-6=-3+2 is how it should look
Now combine the -8x and 3x cause their like terms and also -8 and -6
-5x-14=-3x+2 now add -3 to both sides
-2x-14=2 and add 14 to both sides
-2x=12 all left to do is divide both by -2
X=-6
8 0
3 years ago
Find the positive value of x in the geometric sequence 7x-2,4x+4,3x
Goryan [66]
Hello,


Let's assume k the ratio.


 \left \{ {{3x=k*(4x+4)} \atop {4x+4=k*(7x-2)}} \right. \\\\
 \left \{ {{3x-4kx=4k} \atop {4x-7kx=-2k-4}} \right. \\\\
 \left \{ {{x(3-4k)=4k} \atop {x(4-7k)=-2k-4}} \right. \\\\
 \left \{ {{x=\dfrac{4k}{3-4k} \atop {x=\dfrac{-2k-4}{4-7k} \right. \\\\

\dfrac{4k}{3-4k}=\dfrac{-2k-4}{4-7k}\\\\

36k^2-6k-12=0\\
6k^2-k-2=0\\

\boxed{k= \dfrac{2}{3} \ or\ k= -\dfrac{1}{2}}\\\\

x=\dfrac{4*\dfrac{2}{3} }{3-4*\dfrac{2}{3} }=8\\
x=\dfrac{4*\dfrac{-1}{2} }{3-4*\dfrac{-1}{2} }=-\dfrac{2}{5}\\







\boxed{x= 8 \ or\ x= -\dfrac{2}{5}}\\\\





5 0
3 years ago
What is the area of triangle rst? 6 square units 9 square units 12 square units 18 square units
Butoxors [25]

The area of the considered triangle RST is given by: Option A: 9 sq. units.

<h3>How to find the area of a triangle?</h3>

If we have:

  • Length of its base = b units
  • Its height = h units long,

Then we get:

Area of a triangle = \dfrac{b \times h}{2} \: \rm unit^2

The missing image is attached below.

If we take the base of the triangle as RS, then as the line UT is perpendicular to RS (as RS is parallel to x axis and UT is parallel to y axis) and touching from the base line RS to T, thus, it can be taken as height.

Thus, we have:

Area of RST = half of length of RS (base) times length of UT (height)

As visible from image, we have:

Length of RS = 6 blocks of unit length = 6 units

Similarly, length of UT = 3 units

Thus, we get:

Area of RST = \dfrac{6 \times 3}{2} = 9 \: \rm unit^2

Thus, the area of the considered triangle RST is given by: Option A: 9 sq. units.

Learn more about area of a triangle here:

brainly.com/question/14503701

6 0
3 years ago
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