1 step: if you have to square some number, then you have to multiply this number by itself:
![(a^3)^2=a^3\cdot a^3.](https://tex.z-dn.net/?f=%28a%5E3%29%5E2%3Da%5E3%5Ccdot%20a%5E3.)
2 step: to find the cube of a number you should multiply this number two times by itself:
![a^3=a\cdot a\cdot a.](https://tex.z-dn.net/?f=a%5E3%3Da%5Ccdot%20a%5Ccdot%20a.)
3 step: multiplying a by itself 5 times you get the 6th power of a:
![(a\cdot a\cdot a)\cdot (a\cdot a\cdot a)=a\cdot a\cdot a\cdot a\cdot a\cdot a=a^6.](https://tex.z-dn.net/?f=%28a%5Ccdot%20a%5Ccdot%20a%29%5Ccdot%20%28a%5Ccdot%20a%5Ccdot%20a%29%3Da%5Ccdot%20a%5Ccdot%20a%5Ccdot%20a%5Ccdot%20a%5Ccdot%20a%3Da%5E6.)
Similar way to count
is:
![(a^2)^3=a^2\cdot a^2\cdot a^2=(a\cdot a)\cdot (a\cdot a)\cdot (a\cdot a)=a\cdot a\cdot a\cdot a\cdot a\cdot a=a^6.](https://tex.z-dn.net/?f=%28a%5E2%29%5E3%3Da%5E2%5Ccdot%20a%5E2%5Ccdot%20a%5E2%3D%28a%5Ccdot%20a%29%5Ccdot%20%28a%5Ccdot%20a%29%5Ccdot%20%28a%5Ccdot%20a%29%3Da%5Ccdot%20a%5Ccdot%20a%5Ccdot%20a%5Ccdot%20a%5Ccdot%20a%3Da%5E6.)
It’s A I did it before trust me
Answer:
2 ??? what is the question
Answer:
To find the next number in the sequence, multiply the number before by 2.
By this logic, numbers 4-8 in the sequence would be 152, 304, 608, 1,216, and 2,432
Thus, the 8th term is 2,432