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photoshop1234 [79]

2 years ago

8

HELPPP ASAP!!! PLSSSS!!!!!!

1 answer:

jonny [76]2 years ago

3 0

Answer:

2. B

3.B

4.C

6A. 6

6B. 12

6C. 19.6

6D. 18.75

6E. I cant see

6F. I cant see

Step-by-step explanation:

2. 1/4*40=10

3. type the choice into the calculator

4. 2/5 of 30 or 2/5*30=12

6. A-F type into the calculator

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Need some serious help ASAP (will give brainliest)

abruzzese [7]

I could be wrong (and I apologize if I am), but I believe these are the answers to your questions.

1.) Angle 4
2.) Angle 6
3.) Angle 10
4.) 30 degrees
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10.) 38 degrees

If I turn out to be correct, then I am happy I was able to help you.

3 0

2 years ago

Solve for x 4(x+9)= 3(2x - 7)

ElenaW [278]

Answer: X= 57/2

Hope this helps!

3 0

3 years ago

Read 2 more answers

The width of a large, rectangular-shaped tree farm is 1.9 kilometers. The length of the farm is 4.4 kilometers. What are the bes

Vinvika [58]

Answer:

9 square kilometers

Step-by-step explanation:

Let's round the width to 2.0 kilometers, and round the length to 4.5 kilometers.

We know that area is length times width, so

A = lw

A = 2.0*4.5

<u>A = 9.0 square kilometers</u>

If we do this on the calculator, it's around 9.36 square kilometers, so our estimate was good.

6 0

3 years ago

PLEASE HELP!! I'll make brainliest

Gekata [30.6K]

Sorry people send you links instead of actually helping you

5 0

2 years ago

Find the solution set of this inequality|10x+20| ≤10

Pavlova-9 [17]

Answer:

solution is

[-3,-1]

Step-by-step explanation:

we are given

$|10x+20|\leq 10$

Firstly, we will find critical values

so, let's assume it is equal

$|10x+20|= 10$

now, we can break absolute sign

For $|10x+20|= -(10x+20)$ :

$-(10x+20)= 10$

we can solve for x

$-10x-20= 10$

Add both sides by 20

$-10x-20+20= 10+20$

$-10x= 30$

Divide both sides by -10

and we get

$x=-3$

For $|10x+20|= (10x+20)$ :

$(10x+20)= 10$

we can solve for x

$10x+20= 10$

Subtract both sides by 20

$10x+20-20= 10-20$

$10x= -10$

Divide both sides by 10

and we get

$x=-1$

so, critical values are

$x=-3$

$x=-1$

now, we can draw a number line and locate these values

and then we can check inequality on each intervals

For $(-\infty,-3)$ :

We can select any random value from this interval and plug that in inequality

and we get

we can plug x=-5

$|10\times -5+20|\leq 10$

$|-50+20|\leq 10$

$30\leq 10$

so, this is FALSE

For $[-3,-1]$ :

We can select any random value from this interval and plug that in inequality

and we get

we can plug x=-2

$|10\times -2+20|\leq 10$

$|-20+20|\leq 10$

$0\leq 10$

so, this is TRUE

For $(-1,\infty)$ :

We can select any random value from this interval and plug that in inequality

and we get

we can plug x=0

$|10\times 0+20|\leq 10$

$|0+20|\leq 10$

$20\leq 10$

so, this is FALSE

so, solution is

[-3,-1]

7 0

2 years ago