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2 years ago

YESSSSS! WERE NOT OVER JUST YET I DONT UNDERSTAND THIS MUCH XD PLZ HELP I WILL MARK BRAINLIEST

Mathematics

2 answers:

WARRIOR [948]2 years ago

5 0

Answer:

D) The expression equals 0

Step-by-step explanation:

-8 + 8 = 0

the negative and positive cancel eachother out

BigorU [14]2 years ago

4 0

The answer is D and go to the ER

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Help me !! ASAP

WARRIOR [948]

Answer:

√(8×32)

√(256)

$16$

$is \: your \: answer$

I hope it helps

have a nice day

#Captainpower

5 0

3 years ago

Read 2 more answers

Write the equation of the parabola that has its x-intercepts at (1+<img src="https://tex.z-dn.net/?f=%5Csqrt%7B5%7D" id="TexForm

VladimirAG [237]

Answer:

$y=2x^2-4x-8$

Step-by-step explanation:

<u>Factored form of a parabola</u>

$y=a(x-p)(x-q)$

where:

p and q are the x-intercepts.
a is some constant.

Given x-intercepts:

(1+√5, 0)
(1-√5, 0)

Therefore:

$\implies y=a(x-(1+\sqrt{5}))(x-(1-\sqrt{5}))$

$\implies y=a(x-1-\sqrt{5})(x-1+\sqrt{5})$

To find a, substitute the given point (4, 8) into the equation and solve for a:

$\implies a(4-1-\sqrt{5})(4-1+\sqrt{5})=8$

$\implies a(3-\sqrt{5})(3+\sqrt{5})=8$

$\implies4a=8$

$\implies a=2$

Therefore, the equation of the parabola in factored form is:

$\implies y=2(x-1-\sqrt{5})(x-1+\sqrt{5})$

Expand so that the equation is in standard form:

$\implies y=2(x^2-x+\sqrt{5}x-x+1-\sqrt{5}-\sqrt{5}x+\sqrt{5}-5)$

$\implies y=2(x^2-x-x+\sqrt{5}x-\sqrt{5}x+\sqrt{5}-\sqrt{5}+1-5)$

$\implies y=2(x^2-2x-4)$

$\implies y=2x^2-4x-8$

6 0

1 year ago

John is creating crafts that require 4 2/5 inches of string each. If the string comes in a 50ft spool, how many items can he mak

Elena L [17]

Answer:

Step-by-step explanation:

12 in = 1 ft

600 in = 50ft

$600\div 4\frac{2}{5}$ =

600÷4.4 =

136.3636363...≈136

7 0

2 years ago

Read 2 more answers

Drag the tiles to the boxes to form correct pairs. Polygon ABCD has sides with these lengths: , 5 units; , 4 units; , 4.5 units;

Airida [17]

Answer:

5 units

Step-by-step explanation:

5 0

2 years ago

(2^8 x 3^−5 x 6^0)−2 x 3 to the power of negative 2 over 2 to the power of 3, whole to the power of 4 x 2^28

Veronika [31]

$(2^8\cdot3^{-5}\cdot6^0)^{-2}\cdot\left(\dfrac{3^{-2}}{2^3}\right)^4\cdot2^{28}\\\\=(2^8)^{-2}\cdot(3^{-5})^{-2}\cdot1^{-2}\cdot\dfrac{(3^{-2})^4}{(2^3)^4}\cdot2^{28}\\\\=2^{-16}\cdot3^{10}\cdot\dfrac{3^{-8}}{2^{12}}\cdot2^{28}\\\\=2^{-16}\cdot2^{28}\cdot2^{-12}\cdot3^{10}\cdot3^{-8}\\\\=2^{-16+28+(-12)}\cdot3^{10+(-8)}\\\\=2^0\cdot3^2=1\cdot9=\boxed{9}\\\\Used:\\\\(a\cdot b)^n=a^n\cdot b^n\\\\(a^n)^m=a^{n\cdot m}\\\\a^n\cdot a^m=a^{n+m}\\\\a^{-n}=\dfrac{1}{a^n}$

4 0

3 years ago

Read 2 more answers