Answer:
Step-by-step explanation:
we know that
In this problem ABCD is a rectangle
so
DC=AB
BC=AD
Let
BC ---> the length of rectangle
DC ---> the width of rectangle
we know that
The perimeter of rectangle is equal to
we have
so
simplify
----> equation A
----> equation B
substitute equation B in equation A
Solve for BC
Combine like terms
Divide by 3 both sides
<em>Find the value of DC</em>
----> 
Remember that
DC=AB
therefore
Answer:
your answer is 10/3 (fraction)
Step-by-step explanation:
120-40=80
4 x 6=24
80/24=
- first divide both sides by four and get 20/6
- then divide by 2 to get 10/3 (fraction form)
3x - y = 9
y = -2x + 11
3x - (-2x + 11) = 9
3x + 2x - 11 = 9
3x + 2x = 9 + 11
5x = 20
x = 20/5
x = 4
y = -2x + 11
y = -2(4) + 11
y = -8 + 11
y = 3
solution (where the lines intersect) is (4,3)
5/6 is closest to 1 because it it 1/6 away from 1 and is 5/6 away from 0 and is 2/6 away from 1/2 (referring 1/2 as 3/6) Hope this helps!
Answer:
A) This is correct. The angles of <em>AEB </em>are the angles of <em>DEC. </em>This means that this is true.
B) This is incorrect. This triangle is NOT an isosceles triangle. The angles of an isosceles triangle are supposed to be about 36° for the top angle, and 72° for the other two angles. (At least this is what I was told)
Hope this helps :)
-wait. .___. they both might be true.
According to G oogle: "All the three angles situated within the isosceles triangle are acute, which signifies that the angles are less than 90°. The sum of three angles of an isosceles triangle is always 180°, which means we can find out the third angle of a triangle if the two angles of an isosceles triangle are known."
