1 billion is=1,000,000,000
count the zeros since it has only 10's as the factors
9 zeros
the 10=2 times 5
so there are 10 2's and 10 5's so the prime factorization is
2 times 2 times 2 times 2 times 2 times 2 times 2 times 2 times 2 times 2 times 5 times 5 times 5 times 5 times 5 times 5 times 5 times 5 times 5 times 5 or
2^10 times 5^10
Answer:
0
Step-by-step explanation:
given that we roll a fair die repeatedly until we see the number four appear and then we stop.
the number 4 can appear either in I throw, or II throw or .... indefinitely
So X = the no of throws can be from 1 to infinity
This is a discrete distribution countable.
Sample space= {1,2,.....}
b) Prob ( 4 never appears) = Prob (any other number appears in all throws)
= 
where n is the number of throws
As n tends to infinity, this becomes 0 because 5/6 is less than 1.
Hence this probability is approximately 0
Or definitely 4 will appear atleast once.
With these transversals across parallel lines the angles are either congruent or supplementary (adding to 180) and its pretty easy to figure out which is which, obtuse verse acute in the figure.
Each yellow circle indicates x and the path to the next square. So for example the Start has alternate interior angles, which are congruent, so x is 141 degrees.
Answer:
3.682
Step-by-step explanation:
We don't consider the decimal place or I should say comma so then we read from the first digit as long as it's not zero then until the fourth digit we look at the next digit if it's 5 or greater then we add 1 to the previous digit. And if the next digit is less than 5 then the digit won't change
6.8,6.827,6.86,6.9
1.2,1.203,12.03, 12.301,12.31