Answer:
40π cm2/ min.
Step-by-step explanation:
First, we should begin with an equation we know relating the area of a circle, the pool, and its radius: A=πr2.
Answer:
(16.904 ; 30.660)
Step-by-step explanation:
Given the data :
X = 23.71,17.79,29.87,18.78,28.76
Sample size = 5
Mean = (23.71+17.79+29.87+18.78,+28.76) / 5 = 23.782
Using a calculator, sample standard deviation :
Standard deviation, s = 5.54
Tcritical at α = 0.05, df = 5 - 1 = 4
Using tables ; Tcritical value = 2.7763
Confidence interval :
Mean ± Margin of Error
Margin of Error (MOE) = Tcritical * SE
Margin of Error = Tcritical * s/sqrt (n)
MOE = 2.7763 * 5.54/Sqrt(5) = 6.878
Confidence interval : 23.782 ± 6.878
Lower boundary : 23.782 - 6.878 = 16.904
Upper boundary = 23.782 + 6.878 = 30.66
(16.904 ; 30.660)
Answer:
x = - infinity to 99
Step-by-step explanation:
The values of x must less than 100.
Answer:
<h3><u>Part (a)</u></h3>
<u />
<u>Equation of a circle</u>
where:
- (a, b) is the center
- r is the radius
Given equation:
Comparing the given equation with the general equation of a circle, the given equation is a <u>circle</u> with:
- center = (0, 0)
- radius =
To draw the circle, place the point of a compass on the origin. Make the width of the compass 2.5 units, then draw a circle about the origin.
<h3><u>Part (b)</u></h3>
Given equation:
Rearrange the given equation to make y the subject:
Find two points on the line:
Plot the found points and draw a straight line through them.
The <u>points of intersection</u> of the circle and the straight line are the solutions to the equation.
To solve this algebraically, substitute into the equation of the circle to create a quadratic:
Now use the quadratic formula to solve for x:
To find the coordinates of the points of intersection, substitute the found values of x into
Therefore, the two points of intersection are:
Or as decimals to 2 d.p.:
(2.35, -0.85) and (-0.85, 2.35)
The answer is D
That would be 4 * 10^16 divided by 5 * 10^8
= 4/5 * 10^(16-8)
= 0.8 * 10^8
= 8 * 10^7 in scientific format.