Answer:
16 , step 2 is written incorrectly but I think they want it to be 4 & 19, step 3 is 4 & 19. BTW this is a poorly written question!
Alright here are the answers in order!
a) Independent
b) Dependent
c) 0.9
d) 0.5
I hope this helps!
Answer:
c. start fraction 5 over 6 end fraction
Step-by-step explanation:
there are six numbers on a cube
1, 2, 3, 4, 5, 6
there are 5 other numbers other than 6
5/6
5 = other than 6
6 = total numbers
Part A:
For the first figure it can be seen that the orientation of the pre-image (<span>∆RST) is the same as that of the image (∆R'S'T').
The image is obtained from the pre-image by shifting the pre-image some units down.
Therefore, the </span><span>single transformation that transforms ∆RST to ∆R'S'T' is a translation.
Part B:</span>
<span>
For the second figure it can be seen that the orientation of the pre-image (<span>∆RST) is the same as that of the image (∆R'S'T').
The image is obtained from the pre-image by shifting the pre-image some units down and some units to the right.
Therefore, the </span><span>single transformation that transforms ∆RST to ∆R'S'T' is a translation.
Part C:
</span></span><span>
For the third figure it can be seen that the orientation of the pre-image (<span>∆RST) is not the same as that of the image (∆R'S'T').
The image is obtained from the pre-image by rotating the pre-image some 180 degrees.
Therefore, the </span><span>single transformation that transforms ∆RST to ∆R'S'T' is a rotation.
Part D:
</span></span><span>
For the fourth figure it can be seen that the orientation of the pre-image (<span>∆RST) is not the same as that of the image (∆R'S'T').
The image is obtained from the pre-image by refrecting the pre-image.
Therefore, the </span><span>single transformation that transforms ∆RST to ∆R'S'T' is a reflection.</span></span>
Answer:
Molly has to add 22.86 milliliters of 5% sulfuric acid.
Step-by-step explanation:
Molly has a mixture of 20 ml of 20% sulfuric acid solution.
She mixes this with 5% sulfuric acid solution and in the end she wants a 12% sulfuric acid solution.
We have to find how many milliliters of 5% sulfuric acid we have to add to make it 12% solution.
Let the volume we add be v milliliters.
We are going to equate sulfuric acid.
v = milliliters
v = 22.86 milliliters