Question

Find the equation of a line parallel to y - 5 = 6x - 10 that passes through the point (4, 10). (answer in slope-intercept form) A) y = 6x - 14 B) y = 6x + 14 C) y = -6x - 14 D) y = 1 6 x - 14

Answer 1

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               Find the equation of a line parallel to y-5=6x-10 that passes through (4,10)

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❖ If lines are parallel to each other, they have the same slope.

So the slope of the line parallel to y-5=6x-10 is 6.

Now, since we're also given the point crossed by the line, we write the equation in point-slope form:-

$\sf{y-y_1=m(x-x_1)}$

Substitute 10 for y₁, 6 for m and 4 for x₁:-

$\sf{y-10=6(x-4)}$

On simplification,

$\sf{y-10=6x-24}$

Adding 10 to both sides results in:-

$\sf{y=6x-14}$

So we conclude that Option A is correct.

Good luck.

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