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ycow [4]
2 years ago
14

Please hurry I’ll mark as brainlist

Mathematics
2 answers:
Andrews [41]2 years ago
3 0

Answer:

The first one

Step-by-step explanation:

marshall27 [118]2 years ago
3 0
The answer is the first one: 4096 or 8^4
You might be interested in
What is x if<br> f(x) = -2?
Andrej [43]

<u><em>Answer:</em></u>

<u><em>The answer is 2 or 2x</em></u>

<u><em>Step-by-step explanation:</em></u>

<u><em>Hope this helps!!</em></u>

3 0
2 years ago
You decide to play roulette 4 times, each time betting on red. What is the distribution of X, the number of times you win?
aalyn [17]
  <span> 1.
If betting on red, 18/38 = 9/19 chance of winning, so 10/19 chance of losing
Chance of winning 4 times: (9/19)^4 = 6561/130321 =~ 5.034%
Chance of winning 3 times: (9/19)^3 * (10/19) * C(4,1) = 29160/130321 =~ 22.3755%
Chance of winning 2 times: (9/19)^2 * (10/19)^2 * C(4,2) = 48600/130321 =~ 37.2925%
Chance of winning 1 time: (9/19) * (10/19)^3 * C(4,3) = 36000/130321 =~ 27.624%
Chance of winning 0 times: (10/39)^4 = 10000/130321 =~ 76.7336% </span>
3 0
2 years ago
now find the components nx and ny of n⃗ in the tilted coordinate system of part b. express your answer in terms of the length of
saw5 [17]

The components are Nx= Ncosθ  and Ny= -Nsinθ

<h3>What is a Vector?</h3>

We know that the vector quantities are those quantities that have magnitude as well as direction.

Each vector quantity can be divided into two parts a horizontal and vertical component, the vertical component is known as the sine component while the horizontal component is known as the cosine component.

A vector component is the product of its length and the component angle.

Generally, F sinθ is the vertical component and F cosθ is the horizontal component,

Now, from the diagram the horizontal component of vector 'r' is

Nx= Ncosθ

and, the vertical component will be

Ny= -Nsinθ

this is in the opposite direction

Learn more about vectors here:

brainly.com/question/1600633

#SPJ4

7 0
1 year ago
Marisol is being paid $792 to provide nutrition counseling, It took her 8 hours more than she expected, so
olchik [2.2K]

Answer: 44 hours.

Step-by-step explanation:

Marisol is being paid $792.

We know that the job took her 8 hours more than she expected, so if we define T as the time she expected, this job took her:

T + 8 hours.

The amount of money per hour that she expected is calculated as:

$792/T = X

And for those 8 extra hours, she won $4 less per hour, then we have:

$792/(T + 8hs) = X - $4

Then we have a system of equations:

$792/T = X

$792/(T + 8hs) = X - $4

To solve this, we can notice that in the first equation X is isolated, then we could replace that in the second equation to get:

$792/(T + 8hs) = $792/T - $4

Now we can solve this for T.

$792 = ($792/T - $4)*(T + 8hs)  = $792 + $792*(8hs/T) - $4*T + $32*hs

0 = $792*(8hs/T) - $4*T + $32*hs

Let´s multiply this both sides by T

0*T = ($792*(8hs/T) - $4*T + $32*hs)*T

0 = $792*8hs - $4*T^2 +$32*T*hs

This is a quadratic equation, where i will write this witout units so it is easier to read and follow:

0 = -4*T^2 + 32*T + 792*8

The solutions cab be found by using the Bhaskara´s formula, these are:

T = \frac{-32 +- \sqrt[2]{(32^2 - 4*(-4)*(792*8)} }{2*-4}  = \frac{-32 +-320}{-8}

Then the solutions are:

T = (-32 + 320)/-8 = -36 hours (This is a negative time, and it does not really have a meaning in this problem, so we can discard this option)

The other solution is:

T = (-32 - 320)/-8 = 44 hours.

Then we can conclude that she expected the job would take 44 hours in total.

5 0
2 years ago
If 2^n + 1 is an odd prime for some integer n, prove that n is a power of 2. (H
vovikov84 [41]

Step-by-step explanation:

We will prove by contradiction. Assume that 2^n + 1 is an odd prime but n is not a power of 2. Then, there exists an odd prime number p such that p\mid n. Then, for some integer k\geq 1,

n=p\times k.

Therefore

  1. 2^n + 1=2^{p\times k} + 1=(2^{k})^p + 1^p.

Here we will use the formula for the sum of odd powers, which states that, for a,b\in \mathbb{R} and an odd positive number n,

a^n+b^n=(a+b)(a^{n-1}-a^{n-2}b+a^{n-3}b^2-...+b^{n-1})

Applying this formula in 1) we obtain that

2^n + 1=2^{p\times k} + 1=(2^{k})^p + 1^p=(2^k+1)(2^{k(p-1)}-2^{k(p-2)}+...-2^{k}+1).

Then, as 2^k+1>1 we have that 2^n+1 is not a prime number, which is a contradiction.

In conclusion, if 2^n+1 is an odd prime, then n must be a power of 2.

4 0
3 years ago
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