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guapka [62]
3 years ago
13

Calculate the number of Carbon atoms in C5H110H

Chemistry
1 answer:
serious [3.7K]3 years ago
4 0

Answer:

5 carbon atoms are there in this formula

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Helppppp pleaseeee xx
EleoNora [17]

Answer:

2.5 moles of O₂ = 5 moles of H₂O

Explanation:

The balanced equation for the reaction is given below:

2H₂ + O₂ —> 2H₂O

From the balanced equation above,

1 mole of O₂ reacted to produce 2 moles of H₂O.

Finally, we shall determine the number of mole of H₂O produced by the reaction of 2.5 moles of O₂. This can be obtained as follow:

From the balanced equation above,

1 mole of O₂ reacted to produce 2 moles of H₂O.

Therefore, 2.5 moles of O₂ will react to produce = 2.5 × 2 = 5 moles of H₂O.

Thus,

2.5 moles of O₂ = 5 moles of H₂O

7 0
3 years ago
80 points!!
ikadub [295]
Materials: laser pointer/ flashlight with a paper with a small slit, glass prism

step 1.) turn on the laser pointer point it up to the ceiling.

step 2.) point to prism, explain how the light refracts in the prism. and how it changes.

(I hope this helps!)
6 0
3 years ago
Read 2 more answers
2.92 A 50.0-g silver object and a 50.0-g gold object are both added
Trava [24]

Answer:

82.9 mL  

Explanation:

1. Volume of silver

\begin{array}{rcl}\text{Density}&=& \dfrac{\text{Mass}}{\text{Volume}}\\\\\rho&=& \dfrac{m}{V}\\\\V &=& \dfrac{m}{\rho}\\\\& = & \dfrac{\text{50.0 g}}{\text{10.49 g$\cdot$mL}^{-1}}\\\\& = & \text{4.766 mL}\\\end{array}\\\text{The volume of the silver is $\large \boxed{\textbf{4.766 mL}}$}

2. Volume of gold

\begin{array}{rcl}V& = & \dfrac{\text{50.0 g}}{\text{19.30 g$\cdot$mL}^{-1}}\\\\& = & \text{2.591 mL}\\\end{array}\\\text{The volume of the gold is $\large \boxed{\textbf{2.591 mL}}$}

3. Total volume of silver and gold

V = 4.766 mL + 2.591 mL = 7.36 mL

4 New reading of water level

V = 75.5 mL + 7.36 mL = 82.9 mL

3 0
4 years ago
Is water a solution?<br><br> no<br><br> yes
Advocard [28]

Answer:

no, water is a solvent

Explanation:

A solution is a homogeneous mixture of two substances, so water can only be part of a solution when there is something (a solute) mixed with it, like salt, making it salt water.

Hope that helps.

5 0
3 years ago
How many lithium ions are present in 30.0 ml of 0.600 m li2co3 solution?
Nikolay [14]
First; use the relationship of molarity and moles/liter to find the moles of the solution.
so 0.600M ×0.030L = 0.018 moles
Then use the mole to mole ratio of lithium to lithium carbonate
0.18 × (2 Li ÷1 Li2CO3) = 0.036
and then multiply by Avogadro's number to find the ions of lithium
0.036 moles × (6.022×10^{23} ) = 2.167 ×10∧22 ions Li
4 0
3 years ago
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