Answer:
44.7 degree (3 s.f)
Explanation:
mass of water = 4.10Kg
Initial temperature = 37.5C
Final temperature = x
Heat = 125 kJ = 125000 J
Specific heat capacity = 4180 J/kg°C
These parameters are given by:
H = MCΔT
ΔT = H / MC
ΔT = 125000 / (4.10 * 4180)
ΔT = 7.294
ΔT = T2 - T1
T2 = ΔT + T1
T2 = 7.294 + 37.5
T2 = 44.794 = 44.7 degree (3 s.f)
Answer:
See explanation
Explanation:
% optical purity = specific rotation of mixture/specific rotation of pure enantiomer * 100/1
specific rotation of mixture = 23°
specific rotation of pure enantiomer = 61°
Hence;
% optical purity = 23/61 * 100 = 38 %
More abundant enantiomer = 100% - 38 % = 62%
Hence the pure (S) carvone is (-) 62° is the more abundant enantiomer.
Enantiomeric excess = 62 - 50/50 * 100 = 24%
Hence
(R) - carvone = 38 %
(S) - carvone = 62%
Answer:
Explanation:
To convert from moles to mass, the molar mass must be used.
First, write the chemical formula for carbon monoxide. Since the carbon (C) comes first without a prefix, there is 1 carbon atom. The prefix mono- before oxide means 1, so there is also 1 oxygen (O) atom. The formula is CO.
Next, look up their molar masses on the Periodic Table.
- C: 12.011 g/mol
- O: 15.999 g/mol
Since there is 1 atom of each, the molar masses can be added.
- CO: 12.011 g/mol + 15.999 g/mol = 28.01 g/mol
Use this molar mass as a ratio.
Multiply by the given number of moles:5.55
The moles of carbon monoxide cancel.
Multiply.
The original measurement of moles has 3 significant figures, so our answer must have the same. For the number we calculated, it is the ones place. The 4 in the tenths place tells us to leave the 5.
5.55 moles of carbon monoxide is about 155 grams.