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natali 33 [55]
3 years ago
6

Amount of moles in 3.34x10^34 formula units of Cu(OH)2

Chemistry
1 answer:
Naily [24]3 years ago
4 0

 The amount of  moles in  3.34 x10³⁴  formula unit of Cu(OH)₂ is 5.55 × 10¹⁰  moles

  <u><em>calculation</em></u>

 The  amount  of  moles  is calculated  using  the Avogadro's  law   constant

That  is  1  moles =  6.02 × 10²³  formula units

                 ? moles = 3.34 × 10³⁴ formula  units

<em>by cross  multiplication</em>

= {1 mole  ×3.34 ×10³⁴  formula units ] / 6.02 × 10²³ formula units}  = 5.55 ×10¹⁰  moles


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Answer:

9.25

Explanation:

Let first find the moles of NH_4Cl and NaOH

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number of moles of NaOH = 0.80  mol/L × 50 ×  10⁻³L

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The equation for the reaction is expressed as:

NH^+_{4(aq)} \ + OH^-_{(aq)} ------> NH_{3(g)} \ + H_2O_{(l)}

The ICE Table is shown below as follows:

                            NH^+_{4(aq)} \ + OH^-_{(aq)} ------> NH_{3(g)} \ + H_2O_{(l)}

Initial (M)              0.08            0.04                            0

Change (M)         - 0.04          -0.04                          + 0.04

Equilibrium (M)      0.04             0                                0.04

K_a*K_b = 10^{-14} \ at \ 25^0C

K_a = \frac{10^{-14}}{K_b}

K_a = \frac{10^{-14}}{1.76*10^{-5}}

K_a= 5.68*10^{10}

pK_a = - log \ (K_a)

pK_a = - log \ (5.68*10^{-10})

pK_a = 9.25

pH = pKa + \ log (\frac{HB}{HA} )   for buffer solutions

pH = pKa + \ log (\frac{moles \ of \ base }{ moles\ of \ acid} ) since they are in the same solution

pH = 9.25 + \ log (\frac{0.04 }{ 0.04} )

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The compounds which are made up of the atoms of only two elements are called binary compounds.

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water is also binary because it is also made up of only two elements hydrogen and oxygen.

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