Answer:
c. $504,000
Explanation:
Total cost of new equipment = Price of equipment + Shipping & Installation costs = $3,200,000 + $160,000 = $3,360,000
Increase in working capital = Increase in inventories & account receivables - Increase in accounts payable = $640,000 - $256,000 = $384,000
Total Initial net investment outlay = $3,744,000 ($3,360,000+$384,000)
Project terminal cash-flow = Sale value of equipment (after tax) + Recovery of working capital = $200,000*(1-0.40) + $384,000 = $120,000 + $384,000 = $504,000
Answer:
All of the above
Explanation:
A simple deposit multiplier is the quantity of cash kept in reserve by a bank. It is said to be percentage of the amount in deposit at the bank. If the bank has a deposit multiplier of 20%, it then means that the bank must be able to keep $100 in reserve for every $500 they have in their deposits. Then investors can access the remaining $400 available as bank loans.
The answer is option B. The main challenge of career planning in changing times is that you need to revise your plans often.
The world we live in is dynamic. New inventions, new technology, new methods of doing things always come up with time.
Because of this, when making a career plan, one must be fully aware that the process is not static. That is, changes would occur and as such, you have to revise your plans often so that it is in line with what is obtainable at the time.
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Answer:
Decrease cash and increase land
Explanation:
The transaction is:
Account Debit Credit
Land $105,000
Cash $105,000
Purchased land for business.
Both land and cash are assets: they are debited when they increased, and they are credited when they decrease.
Because cash was used to purchase the land, cash decreases and land increases.
Solution:
Given Information,
Heat input is (
) = 5.5 ×
Btu/h
Combustion efficiency of the boiler (
) = 0.7
Combustion efficiency after turn up (
) = 0.8
Operation Hour (t) = 5200h
Unit cost (c) = 
Calculate heat output from the boiler
=
x 
= 5.5 x
x 0.7
= 3.85 x
Btu/h
Calculate the heat input to the boiler after the tune-up
=
/ 
= 3.85 x
/ 0.8
= 4.8125 x
Btu/h
Calculate the saved energy after the tune-up
=
- 
= 5.5 x
- 4.8125 x
Btu/h
= 0.6875 x
Btu/h
Calculate the annual energy saving (
)
=
x t
= ( 0.6875 x
Btu/h ) ( 5200 hr/yr)
= 3575 x
Btu/h
Calculate the annual cost saving
Annual cost saving =
x Unit cost
= 3575 x
Btu/h x 
= 82225