688,747,536 ways in which the people can take the seats.
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How many ways are there for everyone to do this so that at the end of the move, each seat is taken by exactly one person?</h3>
There is a 2 by 10 rectangular greed of seats with people. so there are 2 rows of 10 seats.
When the whistle blows, each person needs to change to an orthogonally adjacent seat.
(This means that the person can go to the seat in front, or the seats in the sides).
This means that, unless for the 4 ends that will have only two options, all the other people (the remaining 16) have 3 options to choose where to sit.
Now, if we take the options that each seat has, and we take the product, we will get:
P = (2)^4*(3)^16 = 688,747,536 ways in which the people can take the seats.
If you want to learn more about combinations:
brainly.com/question/11732255
#SPJ!
Answer:
B.) Progressive
Step-by-step explanation:
Its schedule of marginal tax rates imposes a higher income tax rate on people with higher incomes, and a lower income tax rate on people with lower incomes. The percentage rate increases at intervals as taxable income increases.
Answer:
P(A) = 2/6
P(A’) = 4/6
Step-by-step explanation:
In probability theory, the complement of any event A is the event [not A], i.e. the event that A does not occur. The event A and its complement [not A] are mutually exclusive and exhaustive. Generally, there is only one event B such that A and B are both mutually exclusive and exhaustive; that event is the complement of A. The complement of an event A is usually denoted as A′, Aᶜ, ¬A or A. Given an event, the event and its complementary event define a Bernoulli trial: did the event occur or not?
Our complement, A’, would then be “rolls a 1, 2, 3, or 4.” We can illustrate this as follows: The event “rolling a 5 or 6” and its complement “rolling a 1, 2, 3, or 4.”
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Sorry if I got that wrong
