The answers is 14 if you follow the equation i just did it on a calculator (attached)
The equation that we can create from this situation is:
i = (190 – 5 x) * (29 + x)
where i is the income and x is the increase in daily rate
Expanding the equation:
i = 5510 + 190x – 145x - 5x^2
i = -5x^2 + 45x + 5510
Taking the 1st derivative:
di/dx = -10x +45
Set to zero to get the maxima:
-10x + 45 = 0
x = 4.5
So the cars should be rented at:
29 + x = 33.5 dollars per day
The maximum income is:
i = (190 – 5*4.5) * (33.5)
i = 5,611.25 dollars
Step-by-step explanation:
Let's represent the number of mochas bought with the variable 
, and the number of lattes bought with the variable 
.
Since there are 
students, the total number of mochas and lattes bought must be . This can be represented with the following equation:
We can also set up another equation based on the total amount spent on the coffe:
If we rearrange the first equation, we can solve for :
If we substitute this into the second equation, we can solve for :
Subtituting this back into the original equation, we can solve for :
Therefore, 9 mochas and 14 lattes were bought.
Answer:
Step-by-step explanation:
She has to save $623.75 a month to get that amount of money!
