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likoan [24]
3 years ago
12

How many moles of HCI are neede to prepare 150 mL of a 1.2 Msolution?​

Biology
2 answers:
nexus9112 [7]3 years ago
3 0
<h3>Answer:</h3>

0.18 moles HCl

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Unit 0</u>

  • Conversion: 1000 mL = 1 L

<u>Aqueous Solutions</u>

  • Molarity = moles of solute / liters of solution
<h3>Explanation:</h3>

<u>Step 1: Define</u>

150 mL

1.2 M

<em>x</em> moles

<u>Step 2: Identify Conversions</u>

mL to L conversion

<u>Step 3: Convert</u>

\displaystyle 150 \ mL(\frac{1 \ L}{1000 \ mL} ) = 0.15 L

<u>Step 4: Solve for Moles</u>

  1. Substitute [Molarity]:                    \displaystyle 1.2 \ M = \frac{x \ moles \ HCl}{0.15 \ L}
  2. Isolate <em>x</em>:                                       \displaystyle 0.18 \ moles \ HCl = x
  3. Rewrite:                                        \displaystyle x = 0.18 \ moles \ HCl

<u>Step 5: Check</u>

<em>We are given 2 sig figs. Follow sig fig rules and round.</em>

Since our final answer is in 2 sig figs, there is no need to round.

Degger [83]3 years ago
3 0

Answer:

0.18 moles HCl

Explanation:

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