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lbvjy [14]
3 years ago
5

What’s 6x-3y=18 in slope int? pls help lol

Mathematics
1 answer:
liraira [26]3 years ago
8 0

Answer:

Using the Slope-intercept form, the slope is - 2.

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Graph each equation<br> Y=-2|-3X+3|+4<br><br> NEED HELP ASAP!!
HACTEHA [7]

Graph the absolute value by using the vertex and a few selected points

Point One: X= -1, Y= -8

Point Two: X= 0, Y= -2

Point Three: X= 1, Y= 4

Point Four: X= 2, Y= -2

Point Five: X= 3, Y= -8

The graph should look something like a mountain or an upside down V

3 0
3 years ago
Find the integral, using techniques from this or the previous chapter.<br> ∫x(8-x)3/2 dx
Soloha48 [4]

Answer:

\int x(8-x)^{3/2}dx= -\frac{16}{5} (8-x)^{\frac{5}{2}} +\frac{2}{7} (8-x)^{\frac{7}{2}} +C

Step-by-step explanation:

For this case we need to find the following integral:

\int x(8-x)^{3/2}dx

And for this case we can use the substitution u = 8-x from here we see that du = -dx, and if we solve for x we got x = 8-u, so then we can rewrite the integral like this:

\int x(8-x)^{3/2}dx= \int (8-u) u^{3/2} (-du)

And if we distribute the exponents we have this:

\int x(8-x)^{3/2}dx= - \int 8 u^{3/2} + \int u^{5/2} du

Now we can do the integrals one by one:

\int x(8-x)^{3/2}dx= -8 \frac{u^{5/2}}{\frac{5}{2}} + \frac{u^{7/2}}{\frac{7}{2}} +C

And reordering the terms we have"

\int x(8-x)^{3/2}dx= -\frac{16}{5} u^{\frac{5}{2}} +\frac{2}{7} u^{\frac{7}{2}} +C

And rewriting in terms of x we got:

\int x(8-x)^{3/2}dx= -\frac{16}{5} (8-x)^{\frac{5}{2}} +\frac{2}{7} (8-x)^{\frac{7}{2}} +C

And that would be our final answer.

8 0
3 years ago
If 7x + 3 = 24, what is the value of 5 - 4x?
Iteru [2.4K]

Answer:

Step-by-step explanation:

7x + 3= 24

7x= 24-3

7x= 21

x= 21/7

x= 3

Then we have that

5-4x

5-4(3)

5-12

Answer= -7

3 0
2 years ago
Find 1.47 divided by 3.5. Does the answer change if you use a different power of 10 to multiply the dividend and the divisor bef
MrRa [10]
<span>the answer to 1.47 divided by 3.5 is 0.42. When you use different power of 10 to multiply the dividend and the divisor, the answer changes to different multiples of 0.42 in terms of 10. The answer could be 0.042 or 4.2 etc depending on the power of 10 used to multiply the dividend and divisor.</span>
5 0
3 years ago
If angle X is an acute angle with tan X = 8/7, what is the value of sec X?
iren [92.7K]

Answer: \frac{\sqrt{113}}{7}

Step-by-step explanation:

As X is an acute angle, all 6 trigonometric functions with an argument of X are positive.

Using the identity 1+\tan^{2} X=\sec^{2} X,

1+\left(\frac{8}{7} \right)^{2}=\sec^{2} X\\\\\sec^{2} X=\frac{113}{49}\\\\\therefore \sec X=\boxed{\frac{\sqrt{113}}{7}}

5 0
1 year ago
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