Write a cubic function whose graph goes through the points: (-5, 0) (1, 0) (2, -2) (4, 0)
1 answer:
Answer:
Step-by-step explanation:
From points (-5,0),(1,0),(4,0) we know it has the form
y=(x+5)(x-1)(x-4)
y=(x^2+4x-5)(x-4)
y=x^3-4x^2+4x^2-16x-5x+20
y=x^3-21x+20
Then it must pass through the point (2,-2) so
-2=[2^3-21(2)+20]b
-2=[8-42+20]b
-2=[-14]b
b=1/7 so the equation is
y=(x^3-21x+20)/7
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