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posledela
3 years ago
15

Which number is rational? /2 10 O 16

Mathematics
1 answer:
larisa86 [58]3 years ago
6 0

Answer:

16

Step-by-step explanation:

Square root of 2 is irrational. This has been proven by the Pythagoreans (there is a simple proof of that).

pi is also known to be irrational although the proof is a bit more demanding.

Square root of 10 can be written as a product of square root of 5 and square root of 2, which themselves are irrational. Any product involving an irrational number is irrational

Square root of 16 = 4. 4 can be written as a fraction 4/1, or 8/2, 16/4, etc. and therefore is rational by definition.

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Colt1911 [192]
More than half received below a 90.
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3 years ago
Can someone help me plsssss
hoa [83]

Answer:

Sorry I don't know this.

Step-by-step explanation:

8 0
3 years ago
Find the equation of the line described.
Lunna [17]

Answer:

y = -1/3x + 4

Step-by-step explanation:

y = 3x +5

current slope m is 3, perpendicular is opposite inverse which is -1/3

Passing through (6,2):

y = mx + b

2 = -1/3(6) + b

2 = -2 + b

b = 4

Use the perpendicular m = -1/3 and b = 4 to form equation of line:

y = mx + b

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5 0
3 years ago
Read 2 more answers
I solve kinda a bit but its hard (Algebra 2)
melisa1 [442]

Answer:

x=9

Step-by-step explanation:

The goal is to combine our knowledge of geometry area and algebra skills to solve this problems.

We know area of rectangle is

l \times w

where l is the length and w is the width. We know that one side is 3 less than the other side. We can use L or W but let use L. Let x replace L

One side is x, while the other side is

x - 3

Both multiply to 54.

x(x - 3) = 54

{x}^{2}  - 3x = 54

{x}^{2}  - 3x  - 54 = 0

(x - 9)(x + 6)

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or

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8 0
3 years ago
You have 9 chairs arranged in a circle, and wish to seat 9 people (one person per seat). The one constraint is that person A can
stiv31 [10]

Answer:

30240 number of ways are there to seat them

Step-by-step explanation:

Total number of ways of arranging 9 people on 9 chairs  in circular manners = (9-1)! = 8! =

number of ways A sit always sit next to B = AB together makes a single and

                                                                       therefore total number of arrangements for this  = 7+(AB) = 8  that is 8  persons sitting in circular manner

number of ways = (8-1)! =7! = 5040

likewise number of arrangements for A and C will be = 5040

Total number of ways such that A cannot sit next to B or C = total ways of 9 persons - total number of A always sitting next to B - total number of ways always sitting next to C  = 8! - 7!-7!

                                        = 40320- 5040-5040

                                        = 30240

=  

5 0
3 years ago
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